2014-01-15 87 views
0

所以,我的问题是,我有一个客户名单(现在有大约10万条记录),每个客户都有收入。当我按国家进行分组时,我可以获得大约60个国家的收入总和。比我更需要通过收入DESC来订购吧,我的查询看起来是这样的:通过mysql订购后创建一个唯一的列值

SELECT s2.i,s1.year,s1.short_c,s1.country,s1.uges FROM 
(SELECT u.year,k.short_c,s.country, IFNULL(ROUND(SUM(u.income)),0) as uges 
    FROM im_income u,im_contact k,td_countries s 
    WHERE u.year=2012 
    AND u.customer_id=k.id 
    AND k.kat='K' 
    AND k.short_c=s.short_c 
    GROUP BY k.short_c, u.year 
    ORDER BY u.year ASC,uges DESC) s1 
CROSS JOIN 
(SELECT @i:[email protected]+1 as i FROM (SELECT @i:= 0) AS i) s2 

而且我知道,这与CROSS JOIN是错误的,因为它不给我我需要什么,但有什么办法在ORDER BY之后创建一个唯一的ID,因为我需要订购具有收入DESC的国家,并且比给他们分配代表排名数字的ID?

结果看起来像现在这样:

+-+----+-------+---------+------+ 
|i|year|short_c|country |uges | 
+-+----+-------+---------+------+ 
|1|2012|USA |United S.|123456| 
+-+----+-------+---------+------+ 
|1|2012|RU  |Russia |23456 | 
+-+----+-------+---------+------+ 

而且我希望它以这种方式,而是通过独有的I值的订单后分配:

+-+----+-------+---------+------+ 
|i|year|short_c|country |uges | 
+-+----+-------+---------+------+ 
|1|2012|USA |United S.|123456| 
+-+----+-------+---------+------+ 
|2|2012|RU  |Russia |23456 | 
+-+----+-------+---------+------+ 
|3| |  |   |  | 
+-+----+-------+---------+------+ 

任何帮助,将不胜感激。

回答

1

我认为这是你在找什么:

SELECT @i := @i + 1 as i, s1.year, s1.short_c, s1.country, s1.uges 
FROM (SELECT u.year, 
      k.short_c, 
      s.country, 
      IFNULL(ROUND(SUM(u.income)),0) as uges 
     FROM im_income u join 
      im_contact k 
      on u.customer_id = k.id join 
      td_countries s 
      on k.short_c = s.short_c 
     WHERE u.year = 2012 AND k.kat = 'K' 
     GROUP BY k.short_c, u.year 
    ) s1 
    CROSS JOIN 
    (SELECT @i:= 0) const 
ORDER BY year, uges desc; 

当结果是“输出”,由订单后,会出现变量赋值。

我还修复了您的join语法。您应该学会在where子句中使用显式join而不是隐式联接。