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我试图实现直方图RGB,但是我的算法不会像在图形程序中那样产生类似于曲面的外观。有关本网站示例图像:计算的直方图看起来不像预期的那样
我的版本是这样的:
正如我理解正确的话,RGB直方图只是测量了每个值在特定的频道频率发生。所以我以这种方式实现它:
public Process(layerManager: dl.LayerManager) {
var surface = layerManager.GetCurrent();
var components = new Uint8Array(1024);
surface.ForEachPixel((arr: number[], i: number): void => {
components[arr[i]] += 1;
components[arr[i + 1] + 256] += 1;
components[arr[i + 2] + 512] += 1;
components[arr[i + 3] + 768] += 1;
});
var histogram = layerManager.GetHistogram();
histogram.Clear();
var viewPort = layerManager.GetHistogramViewPort();
viewPort.Clear();
this.DrawColor(histogram, components, 0, new ut.Color(255, 0, 0, 255));
//histogram.SetBlendMode(ds.BlendMode.Overlay);
//this.DrawColor(histogram, components, 256, new ut.Color(0, 255, 0, 255));
//this.DrawColor(histogram, components, 512, new ut.Color(0, 0, 255, 255));
}
private DrawColor(surface: ds.ICanvas, components: Uint8Array, i: number, fillStyle: ut.Color) {
var point = new ut.Point(0, 255);
surface.BeginPath();
surface.FillStyle(fillStyle.R, fillStyle.G, fillStyle.B, fillStyle.A);
surface.RGBAStrokeStyle(fillStyle.R, fillStyle.G, fillStyle.B, fillStyle.A);
surface.LineWidth(1);
surface.MoveTo(point);
for (var j = i + 256; i < j; ++i) {
point = new ut.Point(point.X + 1, 255 - components[i]);
surface.ContinueLine(point);
}
surface.ClosePathAndStroke();
var viewPort = layerManager.GetHistogramViewPort();
viewPort.DrawImage(surface.Self<HTMLElement>(), 0, 0, 255, 255, 0, 0, viewPort.Width(), viewPort.Height());
}
我是否错过了什么?
你完全正确! – Puchacz