4
我无法弄清楚为什么会发生这种情况。我知道这可能会发生,如果我有某种功能名称“阴影”。但是在这种情况下我怎么能?Pandas series.rename给出TypeError:'str'对象无法调用错误
如果我在终端打开的IPython,然后键入:
import pandas as pd
a = pd.Series([1,2,3,4])
a.rename("test")
我得到类型错误:“海峡”对象不是可调用的。这可能是什么原因造成的?
较长错误味精:
/usr/local/lib/python2.7/site-packages/pandas/core/series.pyc in rename(self, index, **kwargs)
2262 @Appender(generic._shared_docs['rename'] % _shared_doc_kwargs)
2263 def rename(self, index=None, **kwargs):
-> 2264 return super(Series, self).rename(index=index, **kwargs)
2265
2266 @Appender(generic._shared_docs['reindex'] % _shared_doc_kwargs)
/usr/local/lib/python2.7/site-packages/pandas/core/generic.pyc in rename(self, *args, **kwargs)
604
605 baxis = self._get_block_manager_axis(axis)
--> 606 result._data = result._data.rename_axis(f, axis=baxis, copy=copy)
607 result._clear_item_cache()
608
/usr/local/lib/python2.7/site-packages/pandas/core/internals.pyc in rename_axis(self, mapper, axis, copy)
2586 """
2587 obj = self.copy(deep=copy)
-> 2588 obj.set_axis(axis, _transform_index(self.axes[axis], mapper))
2589 return obj
2590
/usr/local/lib/python2.7/site-packages/pandas/core/internals.pyc in _transform_index(index, func)
4389 return MultiIndex.from_tuples(items, names=index.names)
4390 else:
-> 4391 items = [func(x) for x in index]
4392 return Index(items, name=index.name)
4393
参考测试例here。
您使用的是哪个版本的熊猫? – gabra
嗨,这就是我在'pd .__ version__:u'0.17.1''。我尝试过'brew update'和'brew upgrade',所以一切都应该是最新的。 – johnblund
如果您要将标量值输入到'rename' [文档](http://pandas.pydata.org/pandas-docs/stable/whatsnew.html#changes-对重命名) –