2017-03-09 156 views
1

我想训练一个实际值输出的神经网络,我只是给出了网络插值集(看起来像方波),但是后向传播总是不给我非常适合输入,我试图添加更多的输入值和标准化输出的特性,但它似乎没有帮助。网络是3层1输入1隐藏1输出和1输出节点 我如何解决这个问题? 我也使用这个成本函数是否正确?使用反向传播训练实值神经网络

for k = 1:m 

    C= C+(y(k)-a2(k))^2; 
end 

我的代码:

clc; 
clear all; 
close all; 
input_layer_size = 4; 
hidden_layer_size = 60; 
num_labels = 1; 
load('Xs'); 
load('Y-s'); 
theta1=randInitializeWeights(4, 60); 
theta2=randInitializeWeights(60, 1); 
plot (xq,vq) 
hold on 
xq=polyFeatures(xq,4); 
param=[theta1(:) ;theta2(:)]; 

[J ,Grad]= nnCostFunction(param,input_layer_size ,hidden_layer_size,num_labels,xq,vq,0); 

     options = optimset('MaxIter', 50); 
    costFunction = @(p) nnCostFunction(p, ... 
           input_layer_size, ... 
           hidden_layer_size, ... 
           num_labels, xq, vq, 10); 


    [nn_params, cost] = fmincg(costFunction, param, options); 

Theta1 = reshape(nn_params(1:hidden_layer_size * (input_layer_size + 1)), ... 
      hidden_layer_size, (input_layer_size + 1)); 

Theta2 = reshape(nn_params((1 + (hidden_layer_size * (input_layer_size + 1))):end), ... 
      num_labels, (hidden_layer_size + 1)); 

     l=xq(:,1); 
     out =predictTest(Theta1,Theta2,xq); 

      accuracy=mean(double(out == vq)) * 100 
     plot (l,out,'yellow'); 

     hold off 



    function [J grad] = nnCostFunction(nn_params, ... 
     input_layer_size, ... 
     hidden_layer_size, ... 
     num_labels, ... 
     X, y, lambda) 

    y(841:901)=0; 
    y=y/2.2; 

    Theta1 = reshape((nn_params(1:hidden_layer_size * (input_layer_size+1))), ... 
     hidden_layer_size, (input_layer_size +1)); 

    Theta2 = reshape(nn_params((1+(hidden_layer_size * (input_layer_size +1))):end), ... 
     num_labels, (hidden_layer_size +1)); 

    m = size(X, 1); 
    J = 0; 
    Theta1_grad = zeros(size(Theta1)); 
    Theta2_grad = zeros(size(Theta2)); 


    X= [ones(m,1) X]; 

    z1=X*Theta1'; 
    a1 = sigmoid(z1); 
    a1= [ones(size(a1,1),1) a1]; 
    z2=a1*Theta2'; 
    a2= sigmoid(z2); 


    for k = 1:m 

     J= J+(y(k)-a2(k))^2; 

    end 
    J= J/m; 
    Theta1(:,1)=zeros(1,size(Theta1,1)); 
    Theta2(:,1)=zeros(1,size(Theta2,1)); 
    s1=sum (sum (Theta1.^2)); 
    s2=sum (sum (Theta2.^2)); 

    s3= lambda *(s2 +s1); 
    s3=s3/(2*m); 
    J=J+s3; 

    D2=zeros(size(Theta2)); 
    D1=zeros(size(Theta1)); 
    for i= 1:m 

     delta3=a2(i)-y(i); 
     v=[0 sigmoidGradient(z1(i,:))]; 
     delta2=(Theta2'*delta3').*v'; 



     D2=D2+delta3'*a1(i,:) ; 
     D1=D1+delta2(2:end)*X(i,:); 


    end 


    Theta1_grad = D1./m + (lambda/m)*[zeros(size(Theta1,1), 1) Theta1(:, 2:end)]; 
    Theta2_grad = D2./m + (lambda/m)*[zeros(size(Theta2,1), 1) Theta2(:, 2:end)]; 

    grad = [Theta1_grad(:) ; Theta2_grad(:)]; 


    end 



    function W = randInitializeWeights(L_in, L_out) 


    epsilon_init = 0.5; 
    W = rand(L_out, 1 + L_in)*2*epsilon_init - epsilon_init; 

    end 

输入是1:9插0.01增量和目标0之间是数字:2.2像方形脉冲

linear interpolation of data vs predicted in red

updated after increasing epochs

+0

欢迎来到Stack Overflow。您能否提供更多关于网络拓扑和一些示例输入和输出数据的信息。还请包括整个算法以及权重初始化。 –

+0

谢谢,我已更新内容 –

+0

您可以为每个输入添加一个预期输出数据的小表吗? –

回答

0

请注意,红线永远不会为零(最低约0.4),这意味着训练的权重永远不会带来网络输出零(我的意思是重量需要有足够的负和偏见或者是完全缺失或不否定在某些细胞

  1. 将信号从[-1到1]进行缩放,并使用权重和偏差来训练网络以查看影响。重量和偏见都是必需的。
  2. 这里使用的简单神经网络不适合像方波那样的时间序列预测。使用预测模型,如here时间序列
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当我在matlab中使用简单的拟合应用程序时,它会生成一个很好的拟合输出 –

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简单拟合是非神经的,可能会使用我在这里分享的技巧。拟合“实值时间信号”时,这两点都很重要 – SACn