好的,这是我的问题。java单线程安全
我需要创建一个套接字程序,可以处理来自我的客户端应用程序的多个连接(让我们称它为apps1)。我使用线程处理这个问题(所以每个连接都被抛入一个新线程)
问题是我可以接受来自所有打开的连接的请求,但是当我想发送响应时,我必须通过最新的连接发送它。所以如果我有3个连接(con1,con2,con3),我可以接受来自con1,con2和con3的请求,但我必须通过con3发送响应(假设con3是最新连接)
我想过使用单例,使用PrintWriter参数。所以每次有一个新的连接,他们调用单例并更新参数,当我想发送响应时,我在发送之前先获取PrintWriter。
这里是我的Singleton类:
public class Singleton {
private static final Singleton instance = new Singleton();
PrintWriter out;
public static Singleton getInstance() {
return instance;
}
public Singleton()
{
if (instance != null) {
throw new IllegalStateException("Already instantiated");
}
}
public PrintWriter getPrintWriter()
{
return this.out;
}
public void updatePrintWriter (PrintWriter out){
this.out = out;
}
}
这是我的主要程序:
public class SocketAccept{
private ServerSocket mainSocket;
private Socket clientSocket;
public SocketAccept (int portNumber) {
Singleton s = Singleton.getInstance();
do {
try {
mainSocket = new ServerSocket(portNumber);
clientSocket = mainSocket.accept();
s.updatePrintWriter(new PrintWriter(clientSocket.getOutputStream(), true));
ClientThread (clientSocket);
} catch (IOException ex) {
Logger.getLogger(TestClass.class.getName()).log(Level.SEVERE, null, ex);
}
}while (true);//need to change this into thread pool or connection pool
}
}
,这是我的线程处理插座:
public class ClientThread extends Thread {
private Socket cs;
Singleton s = Singleton.getInstance();
PrintWriter out;
private String read(Socket sc) {
String request = "";
//read request here
return request;
}
private String process(String request) {
String response = "";
//process request here
return response;
}
public ClientThread(Socket clientSocket) {
this.cs = clientSocket;
}
@Override
public void run() {
String requestMsg = "";
String responseMsg = "";
do {
requestMsg = read(cs);// read the message
if (requestMsg.equalsIgnoreCase("SHUTDOWN")) {
break;
}
responseMsg = process(requestMsg);
out = s.getPrintWriter();
out.write(responseMsg);
} while (true);
}
}
做我做到了对?或者单身人士不可能做到这一点?
感谢您的帮助。
您能否解释为什么所有打开的连接必须始终只打印到最新的流? – 2011-02-11 04:44:42
你想要一张海报来解释他们的要求吗?这不是有点傻吗?这不像他在问一个技术上不可行的问题。 – 2011-02-11 04:49:40