SQL查询获取真实日期和日期时间差异

Question

我需要获取已经开始但尚未完成的旅程。到目前为止，我有这个。

//DepartureDate and Returndate are Datetime Types 

    $sql = "SELECT * FROM Orders WHERE departureDate <= GETDATE() >= returndate"; 

Answer 1

$sql = "SELECT * FROM Orders WHERE departureDate > GETDATE() AND returndate <= GETDATE()"; 

Answer 2

假设你正在使用SQL Server，刚刚突破的逻辑分为两个部分：

SELECT o.* 
FROM Orders o 
WHERE o.departureDate <= GETDATE() AND 
     GETDATE() >= o.returndate