使用SQL Select提取不同的特殊字符

我有一个Table Company。我需要知道公司名称中的特殊字符是什么。使用SQL Select提取不同的特殊字符

考虑样品表

S.No.  CompanyName 
__________________________________ 
1.  24/7 Customers 
2.  Rose & Co. 
3.  Rose Inc. Corp. 
4.  Rose Pvt. Ltd.,

从上面的表格，我需要选择只有鲜明的特殊字符知道什么是所有的特殊字符都参与了公司名称

的上表的输出应为/&.,

来源

2016-12-07 B.Balamanigandan

你是如何定义的特殊字符？非字母，但不是空格？ – jarlh

如果条目仅用ASCII，则可以使用范围查询完成。在Unicode中可能不那么容易。 – Namphibian

有一个地方，你需要确定你的 “常规” 字

select '%[^a-zA-Z0-9 ]%'

with prm (regular_char) 
     as 
     (
      select '%[^a-zA-Z0-9 ]%' 
     ) 

     ,cte (special_char,string_suffix) 
     as 
     (
      select ''    as special_char 
        ,CompanyName  as string_suffix 

      from t 

      union all 

      select substring (string_suffix,special_char_ind,1)     as special_char 
        ,substring (string_suffix,special_char_ind+1,len(string_suffix)) as string_suffix 

      from (select string_suffix 
          ,nullif(patindex(prm.regular_char,string_suffix),0) as special_char_ind 
        from cte,prm 
        where string_suffix <> '' 
        ) t 

      where special_char_ind is not null 

     ) 

select  special_char 
      ,ascii(special_char) as ascii_special_char 
      ,count(*)   as cnt  

from  cte 

where  special_char <> '' 

group by special_char 

option  (maxrecursion 0)

+--------------+--------------------+-----+ 
| special_char | ascii_special_char | cnt | 
+--------------+--------------------+-----+ 
|    | 9     | 1 | 
+--------------+--------------------+-----+ 
| &   | 38     | 1 | 
+--------------+--------------------+-----+ 
| ,   | 44     | 1 | 
+--------------+--------------------+-----+ 
| .   | 46     | 5 | 
+--------------+--------------------+-----+ 
|/   | 47     | 1 | 
+--------------+--------------------+-----+

来源

2016-12-07 10:31:01

试试这个，

declare @t table(SNo int,CompanyName varchar(30)) 
insert into @t VALUES 
(1,'24/7 Customers') 
,(2,'Rose & Co.') 
,(3,'Rose Inc. Corp.') 
,(4,'Rose Pvt. Ltd.,') 

;With CTE as 
(
select sno 
,stuff(CompanyName,PATINDEX('%[,[email protected]\.&/]%',CompanyName),1,'') CompanyName 
,SUBSTRING(CompanyName,PATINDEX('%[,[email protected]\.&/]%',CompanyName),1) spcol from @t 
union ALL 

select sno, 
replace(CompanyName,SUBSTRING(CompanyName,PATINDEX('%[,[email protected]\.&/]%',CompanyName),1),'') 
,SUBSTRING(CompanyName,PATINDEX('%[,[email protected]\.&/]%',CompanyName),1) 
from cte 
where PATINDEX('%[,[email protected]\.&/]%',CompanyName)>0 
) 

select distinct spcol 

from cte

来源

2016-12-07 11:39:56 KumarHarsh

使用SQL Select提取不同的特殊字符

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