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我有一个简单的VHDL设计和测试平台，它不会产生预期的输出。 ISim显示所有输出的'U'，直到达到'运行'状态（myState ='1'）。然后他们显示0和X值。当ENABLE为'0'时，第一个PROCESS块应将所有输出设置为'0'。测试台切换ENABLE 0-1-0以确保事件触发过程，但输出保持'U'。设计，测试或两者都存在问题吗？ISim为所有输出显示U
VHDL
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
entity TestHarness1 is
port (
ADAT_WDCLK : in std_logic;
ADAT_BCLK: in std_logic;
ADAT_OUT12: in std_logic;
ENABLE: in std_logic;
PCM_FS : out std_logic;
PCM_CLK : out std_logic;
PCM_DIN : out std_logic
);
end TestHarness1;
architecture Behavioral of TestHarness1 is
--type state is (STOPPED, RUNNING);
signal tmp : std_logic;
signal myState : std_logic;
begin
PCM_DIN <= tmp;
-- State management process
process (ENABLE, ADAT_WDCLK) begin -- Eval on input changes
if (ENABLE = '0') then
myState <= '0'; --STOPPED;
PCM_FS <= '0'; -- All outputs muted
PCM_CLK <= '0';
tmp <= '0';
else
if (myState = '0' and rising_edge(ADAT_WDCLK)) then
-- Move to running state only at start of a frame
myState <= '1'; --RUNNING;
end if;
end if;
end process;
-- Output process
process (ADAT_WDCLK, ADAT_BCLK, myState) variable counter: integer := 0; begin
-- Only do something if we are in running state, process above
-- sets outputs when stopped.
if (myState = '1') then
-- Pass the clocks through, inverting the bit clock
PCM_FS <= ADAT_WDCLK;
PCM_CLK <= not ADAT_BCLK;
-- Generate fixed bit pattern data '11000101'
if rising_edge(ADAT_WDCLK) then
-- This would happen naturally since there are 4 bytes per word clock
counter := 0;
end if;
if falling_edge(ADAT_WDCLK) then
-- This would happen naturally since there are 4 bytes per word clock
counter := 0;
end if;
if rising_edge(ADAT_BCLK) then -- Change data state only on falling edge of output PCM_CLK
if counter = 0 or counter = 1 or counter = 5 or counter = 7 then
tmp <= '1';
else
tmp <= '0';
end if;
if (counter = 7) then
counter := 0; -- Reset counter
else
counter := counter + 1; -- Just inc counter
end if;
end if;
end if;
end process;
end Behavioral;
试验台
LIBRARY ieee;
USE ieee.std_logic_1164.ALL;
ENTITY TH1TestBench3 IS
END TH1TestBench3;
ARCHITECTURE behavior OF TH1TestBench3 IS
-- Component Declaration for the Unit Under Test (UUT)
COMPONENT TestHarness1
PORT(
ADAT_WDCLK : IN std_logic;
ADAT_BCLK : IN std_logic;
ADAT_OUT12 : IN std_logic;
ENABLE : IN std_logic;
PCM_FS : OUT std_logic;
PCM_CLK : OUT std_logic;
PCM_DIN : OUT std_logic
);
END COMPONENT;
--Inputs
signal ADAT_WDCLK : std_logic := '0';
signal ADAT_BCLK : std_logic := '0';
signal ADAT_OUT12 : std_logic := '0';
signal ENABLE : std_logic := '0';
--Outputs
signal PCM_FS : std_logic;
signal PCM_CLK : std_logic;
signal PCM_DIN : std_logic;
-- Clock period definitions. Note WDCLK is defined in terms of the bit clock
-- to insure they are exactly in sync.
constant ADAT_BCLK_period : time := 326 ns; -- About 3.072MHz (https://www.sensorsone.com/frequency-to-period-calculator/)
constant ADAT_WDCLK_period : time := ADAT_BCLK_period * 64; -- 48KHz
BEGIN
-- Instantiate the Unit Under Test (UUT)
uut: TestHarness1 PORT MAP (
ADAT_WDCLK => ADAT_WDCLK,
ADAT_BCLK => ADAT_BCLK,
ADAT_OUT12 => ADAT_OUT12,
ENABLE => ENABLE,
PCM_FS => PCM_FS,
PCM_CLK => PCM_CLK,
PCM_DIN => PCM_DIN
);
-- Clock process definitions
ADAT_WDCLK_process :process
begin
ADAT_WDCLK <= '0';
wait for ADAT_WDCLK_period/2;
ADAT_WDCLK <= '1';
wait for ADAT_WDCLK_period/2;
end process;
ADAT_BCLK_process :process
begin
ADAT_BCLK <= '1';
wait for ADAT_BCLK_period/2;
ADAT_BCLK <= '0';
wait for ADAT_BCLK_period/2;
end process;
-- Stimulus process
stim_proc: process
begin
-- hold reset state for 100 ns.
wait for 100 ns;
ENABLE <= '1';
wait for 100 ns;
ENABLE <= '0';
wait for 7500 ns;
ENABLE <= '1';
wait for ADAT_WDCLK_period*10;
-- insert stimulus here
wait;
end process;
END;
ISIM示出了在模拟早期使能脉冲，但输出保持 'U'，直到与使WCLK的上升沿= 1。然后他们开始改变（按照设计），但他们显示了一些X值。
改性VHDL
作为参考，这里是解决在模拟输出将U和X的问题的改性VHDL。但是，PCM_DIN输出有一个功能问题，似乎是延迟一个（BCLK）周期。在ENABLE之后第一次ADAT_WDCLK变为高电平时，我预计它是'1'。但是直到BLCK周期后才会进入'1'。
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
entity TestHarness1 is
port (
ADAT_WDCLK : in std_logic;
ADAT_BCLK: in std_logic;
ADAT_OUT12: in std_logic;
ENABLE: in std_logic;
PCM_FS : out std_logic;
PCM_CLK : out std_logic;
PCM_DIN : out std_logic
);
end TestHarness1;
architecture Behavioral of TestHarness1 is
--type state is (STOPPED, RUNNING);
signal tmp : std_logic;
signal myState : std_logic;
begin
PCM_DIN <= tmp;
-- State management process
process (ENABLE, ADAT_WDCLK) begin -- Eval on input changes
if (ENABLE = '0') then
myState <= '0'; --STOPPED;
else
if (myState = '0' and rising_edge(ADAT_WDCLK)) then
-- Move to running state only at start of a frame
myState <= '1'; --RUNNING;
end if;
end if;
end process;
-- Output process
process (ADAT_WDCLK, ADAT_BCLK, myState) variable counter: integer := 0; begin
-- Only do something if we are in running state
if (myState = '0') then
PCM_FS <= '0'; -- All outputs muted
PCM_CLK <= '0';
tmp <= '0';
elsif (myState = '1') then
-- Pass the clocks through, inverting the bit clock
PCM_FS <= ADAT_WDCLK;
PCM_CLK <= not ADAT_BCLK;
if rising_edge(ADAT_BCLK) then -- Generate fixed serial bit pattern
if counter = 0 or counter = 1 or counter = 5 or counter = 7 then
tmp <= '1';
else
tmp <= '0';
end if;
if (counter = 7) then
counter := 0; -- Reset counter
else
counter := counter + 1; -- Just inc counter
end if;
end if;
end if;
end process;
end Behavioral;
上述（包括内部myState信号）...的ISIM为什么PCM_DIN延迟一个周期BCLK？
即使治愈多个驱动程序，您的代码也不会显示合成条件。似乎不可能在一个时钟的两个边沿上清除计数器并用另一个时钟递增。 – user1155120
清除WDCLK边沿上的计数器无论如何都是冗余的，它每8位就会包装一次，并且在字时钟周期内发送的整数个字节（因此它在时钟周期的开始/结束时始终为零）。所以我删除了这些陈述。 – user3191192