选择具有本周内值的日期字段的行

Question

我想从当前星期内的日期字段具有值的表中选择所有行。我想要从当周的星期一到当天的行。

例子：

 
ID adate 
--------------- 
1 11-11-2010 
2 12-11-2010 
3 13-11-2010 
4 14-11-2010 
5 15-11-2010 

我想在这种情况下，行是：

 
ID adate 
--------------- 
4 14-11-2010 //this week's Monday 
5 15-11-2010 //till today 

Answer 1

这将工作从星期日到星期六一周。从周一如果你想星期你必须适应它星期日：

select * 
    from myTable 
where aDate between 
     cast('now' as date) - extract(weekday from cast('now' as date)) --prev sunday 
     and 
     cast('now' as date) - extract(weekday from cast('now' as date)) + 6 --next saturday 
     ; 

Answer 2

我写在MS SQL：

declare @today as datetime 
declare @first_day_of_week datetime 
set @today = convert(varchar, getDate(), 101) 
set @first_day_of_week = dateadd(day, -(DATEPART(WEEKDAY, @today) - 1), @today) 
select * 
from [table] 
where adate between @first_day_of_week and @today 

星期日是一周的开始。