SQL选择日期范围内的每个日期的所有内容，每个日期有多个值

Question

我试过搜索，但我不完全确定如何提前道歉，如果这已在其他地方得到解答。

我正在尝试选择日期范围（包括那个日期没有值的地方）的多个值之间的所有内容。我没有真正解释过，但下面是我之后输出的一个例子。

Date Campaign Channel Transaction 
01/01/2015 a Online Sale 
01/01/2015 b Online Sale 
01/01/2015 c Online Sale 
01/01/2015 a Online Cancellation 
01/01/2015 b Online Cancellation 
01/01/2015 c Online Cancellation 
01/01/2015 a Offline Sale 
01/01/2015 b Offline Sale 
01/01/2015 c Offline Sale 
01/01/2015 a Offline Cancellation 
01/01/2015 b Offline Cancellation 
01/01/2015 c Offline Cancellation 
02/01/2015 a Online Sale 
02/01/2015 b Online Sale 
02/01/2015 c Online Sale 
02/01/2015 a Online Cancellation 
02/01/2015 b Online Cancellation 
02/01/2015 c Online Cancellation 
02/01/2015 a Offline Sale 
02/01/2015 b Offline Sale 
02/01/2015 c Offline Sale 
02/01/2015 a Offline Cancellation 
02/01/2015 b Offline Cancellation 
02/01/2015 c Offline Cancellation 

我能够选择日期范围之间，每天却无法工作，如何选择每天用即使没有返回结果每个结果。

编辑 - 添加了解决方案，我发现

OK，所以我有这似乎是为我工作的解决方案。可能有这样做的更好的方式和任何建议表示赞赏，但这里是我现在做

Declare @CC TABLE (Campaign varchar(50)) 
DECLARE @Channel Table (Channel Varchar(255)) 
DECLARE @TYPE TABLE (Transaction_Type varchar(255)) 
Insert Into @CC (Campaign) Values ('1') 
Insert Into @CC (Campaign) Values ('2') 
Insert Into @Channel (Channel) Values ('Online') 
Insert Into @Channel (Channel) Values ('Inbound') 
Insert Into @TYPE (Transaction_Type) Values ('Sale') 
Insert Into @TYPE (Transaction_Type) Values ('Cancellation') 
DECLARE 
@StartDate DATE = Dateadd(YY,-3,DATEADD(yy, DATEDIFF(yy,0,getdate()), 0)), 
@EndDate DATE = Getdate() 
SELECT 
DATEADD(DAY, nbr - 1, @StartDate) as Dates, 
Campaign, 
Channel, 
Transaction_Type 
FROM (SELECT ROW_NUMBER() OVER (ORDER BY c.object_id) AS Nbr 
FROM sys.columns c) nbrs, 
@CC, @Channel, @TYPE WHERE nbr - 1 <= DATEDIFF(DAY, @StartDate, @EndDate) 
Order by Dates asc, Campaign asc, Channel asc, Transaction_Type asc 

Answer 1

纯SQL（并且没有递归的CTE），我怕你会需要a numbers table了点。

的基本思路将是：

• 确定n，你的开始和结束日期之间的日期数，
• 选择数字1〜n从你的号码表，
• 将数字（以天为单位）添加到开始日期。

这应该会产生一个从开始到结束日期的日期列表，您可以外部加入原始结果集以“填补空白”。

Answer 2

我使用的表值函数返回的所有日期范围（here）..

你可以做小的变化（如重命名，日期时间 - >日期，删除字符列），以满足您的需求。

Create Function [dbo].[IntervalaDatumi] 
(
    @DatumsNo DateTime, 
    @DatumsLidz DateTime 
) 
Returns @tab Table 
    (
     Datums DateTime, 
     DatumsChar char(10) 
    ) 
As 
Begin 
    Declare @Dienas int 
    Declare @i int 
    Set @Dienas = DateDiff(Day, @DatumsNo, @DatumsLidz) 

    Set @i = 0; 
    While (@Dienas > @i) 
    Begin 
     Insert Into @tab(Datums, DatumsChar) 
      Values (DateAdd(Day, @i, @DatumsNo), Convert(Char(10), DateAdd(Day, @i, @DatumsNo), 104)) 
     Set @i = @i + 1 
    End 
    return 
End 

Answer 3

你可以用CTE来做。

DECLARE 
    @start date = '1900-01-01', 
    @end date = '1900-01-10'; 

with dateRange (myDate) AS (
    select @start myDate 
    UNION ALL 
    select DATEADD(DAY,1,myDate) from dateRange 
    where 
     myDate <= @end 
) 
select 
    * 
from dateRange D 
inner join yourTable T on 
    D.myDate = T.[Date] 
OPTION (MAXRECURSION 365) 

随着全外连接

DECLARE 
    @start date = '1900-01-01', 
    @end date = '1900-01-10'; 

with dateRange (myDate) AS (
    select @start myDate 
    UNION ALL 
    select DATEADD(DAY,1,myDate) from dateRange 
    where 
     myDate <= @end 
) 
select 
    * 
from dateRange D 
full outer join @CC C ON 
    1=1 
full outer join @Channel CH ON 
    1=1 
full outer join @TYPE Ty ON 
    1=1 
left join yourTable T on 
    D.myDate = T.[Date] and 
    C.Campaign = T.[Campaign] and 
    CH.Channel = T.[Channel] and 
    Ty.[Transaction_Type] = T.[Transaction_Type] 
OPTION (MAXRECURSION 365)