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'arr'数组是根据用户输入动态创建的，因此其内容在正常运行的版本中发生更改。用户输入可以是任意长度，因此可能不一定包含5个单词。问题是，我不确定如何动态创建words对象，使其具有不同数量的子项，以便将其推送到combos的正确成员。JQuery：将不同长度的动态分配对象推送到对象
var arr = [
[
["this", 0],
["is", 1],
["a", 2],
["complete", 3],
["sentence", 4],
["with", 5],
["index", 6],
["data", 7]
]
];
var partOne = {
two: [],
three: [],
four: [],
five: []
}
var len = arr.length;
var print = [];
for (var i = 0; i < len; i++) {
var lenGr = arr[i].length;
for (var j = 0; j < lenGr - 1; j++) {
partOne.two.push({
"words": {
"word1": arr[i][j],
"word2": arr[i][j + 1]
}
});
}
for (j = 0; j < lenGr - 2; j++) {
partOne.three.push({
"words": {
"word1": arr[i][j],
"word2": arr[i][j + 1],
"word3": arr[i][j + 2]
}
});
}
for (j = 0; j < lenGr - 3; j++) {
partOne.four.push({
"words": {
"word1": arr[i][j],
"word2": arr[i][j + 1],
"word3": arr[i][j + 2],
"word4": arr[i][j + 3]
}
});
}
for (j = 0; j < lenGr - 4; j++) {
partOne.five.push({
"words": {
"word1": arr[i][j],
"word2": arr[i][j + 1],
"word3": arr[i][j + 2],
"word4": arr[i][j + 3],
"word5": arr[i][j + 4]
}
});
}
}
console.log("Current solution : ");
console.log(partOne);
var partTwo = {
two: [],
three: [],
four: [],
five: []
};
for (i = 0; i < len; i++) {
var lenGr = arr[i].length;
$.each(partTwo, function(ind, val) {
for (var j = 1; j < 4; j++) {
for (var k = 0; k < lenGr - j; k++) {
// Populate 'partTwo' dynamically, in the same format as partOne.
}
}
});
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
那是你实际的数组定义是什么？它的语法完全被破坏了。 –
请点击''''''片段编辑器并创建一个[mcve] – mplungjan
您的第一个'var arr = [0 = [0 = [“this”，0]，1 = [“is”，1]，2 = [ 3 = [“complete”，3]，4 = [“sentence”，4]，5 = [“with”，5]，6 = [“index”，6]，7 = [“ “数据”，7]]];'已无效的语法 – gurvinder372