乘记录我的成熟

Question

输入：

我有4个表中的列：

KONTO CUSTOMER_NUMBER COLLATERAL_TYPE MATURITY 

Konto的独特价值，到期日价值，我需要繁殖。

例子：

KONTO CUSTOMER_NUMBER COLLATERAL_TYPE MATURITY 
-------------------------------------------------- 
1   000234   H    4 
2   000234   G    3 
3   212567   H    5 

我需要创建表，每KONTO乘以我的最大的成熟度和每个客户的抵押品类型。也许它更容易说，每个抵押品应该有记录FER每年到期

输出：

KONTO CUSTOMER_NUMBER COLLATERAL_TYPE MATURITY 
------------------------------------------------- 
1   000234   H    1 
1   000234   H    2 
1   000234   H    3 
1   000234   H    4 
2   000234   G    1 
2   000234   G    2 
2   000234   G    3 
3   212567   H    1 
3   212567   H    2 
3   212567   H    3 
3   212567   H    4 
3   212567   H    5 

我从其他公司的同事们成功地做到这一点，但我不知道怎么办。

我在MS Access中使用MS Access/SQL。

谢谢你，我的英文不好

Answer 1

抱歉，这是在MS Access，它不具有热膨胀系数和窗函数真的很痛苦。一种方法是：

select KONTO, CUSTOMER_NUMBER, COLLATERAL_TYPE, 1 as MATURITY 
from t 
where MATURITY >= 1 
union all 
select KONTO, CUSTOMER_NUMBER, COLLATERAL_TYPE, 2 as MATURITY 
from t 
where MATURITY >= 2 
union all 
select KONTO, CUSTOMER_NUMBER, COLLATERAL_TYPE, 3 as MATURITY 
from t 
where MATURITY >= 3 
union all 
select KONTO, CUSTOMER_NUMBER, COLLATERAL_TYPE, 4 as MATURITY 
from t 
where MATURITY >= 4 
union all 
select KONTO, CUSTOMER_NUMBER, COLLATERAL_TYPE, 5 as MATURITY 
from t 
where MATURITY >= 5; 

当然，您将不得不重复这种模式，直到您的最大成熟度。

Answer 2

您可以使用笛卡尔（乘）查询：

SELECT DISTINCT 
    KontoTable.Konto, 
    KontoTable.Customer_Number, 
    KontoTable.Collateral_Type, 
    10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10) AS Maturity 
FROM 
    MSysObjects AS Uno, 
    MSysObjects AS Deca, 
    KontoTable 
WHERE 
    ((10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10)) 
    Between 1 And KontoTable.Maturity);