作为zend框架中的初学者,我需要一些帮助来编写sql查询。 这是我的查询: SELECT
COUNT(*) AS Ouvert , SUBSTRING_INDEX(emails.email_value, '@', -1) AS FAI, track_open.open_date
FROM emails, track_open
WHERE emails.email_i
在哪里做这样的查询,我该怎么办? SELECT * FROM hotels WHERE name LIKE '%mykey%' AND country_id = '12'
我已经这样做了,但我们绝不能: $select = $this->sql->select();
$select->from(self::TABLE);
if ($params['key'])
{
$wher
从下面的方法中收到此错误? 2013-10-02T14:20:05+01:00 ERR (3): exception 'Zend_Db_Table_Select_Exception' with message 'Select query cannot join with another table' in /usr/share/php/Zend/Db/Table/Select.php:215 cl
我有一个ContactsTable.php模块和功能如下: public function getContactsByLastName($last_name){
$rowset = $this->tableGateway->select(array('last_name' => $last_name));
$row = $rowset->current();
if (