我想从Oracle中的存储函数返回的查询。这个简单的尝试失败: CREATE OR REPLACE TYPE GetObjectsForFolderObjectType IS OBJECT (
FOLDER_ID NUMBER(9), OBJECT_ID NUMBER(9)
);
CREATE OR REPLACE TYPE GetObjectsForFolderTableType
我不知道是什么问题,为什么它给我的错误在运行函数 这里是我的SQL: CREATE FUNCTION `test`.`GetProcessorMethodID` (processor_id INT, method_id INT)
RETURNS INTEGER
BEGIN
DECLARE id INT;
SET @id := (SELECT `processor_metho
我有如下所示 type respond_field
IS
record
(
provider_id VARCHAR2(100),
provider_name VARCHAR2(100));
type respond_field_group
IS
TABLE OF respond_field INDEX BY BINARY_INTEGER
我有这个程序 ALTER PROCEDURE [dbo].GetHerdByUserProc(@user int)
As
begin
Declare
@GroupId uniqueidentifier,
@UserTrade bit
Set @GroupId = (select tbUser.group_id from tbUser
我写了一个MySQL的函数,计算价格: CREATE DEFINER=`[USER]`@`[HOST]` FUNCTION `calculatePrice`(id INT)
RETURNS DECIMAL(8,2) DETERMINISTIC
BEGIN
IF id=10 THEN
RETURN 899;
ELSE
RETURN 710;