所以我试图将命令的输出存储到变量中。我不希望它虽然运行命令时显示输出... 我已经把现在的代码如下... def getoutput(*args):
myargs=args
listargs=[l.split(' ',1) for l in myargs]
import subprocess
output=subprocess.Popen(listargs[
我得到这个错误与我的ListView: java.lang.IllegalStateException: The content of the adapter has changed but ListView did not receive a notification. Make sure the content of your adapter is not modified from a ba
我有一个数据包侦听器,用于检测数据包何时到达,并在发生这种情况时需要刷新ArrayAdapter。问题是,如果我尝试访问adapter.notifyDataSetChanged()方法,则会引发异常: Exception in packet listener: android.view.ViewRootImpl$CalledFromWrongThreadException: Only the or
期间滚动在以下项目here is example 我使用的是.notifyDataSetChanged();这种方法.post(new Runnable(){增加新的项目 private void addItemsToList() {
int randomVal = MIN + (int) (Math.random() * ((MAX - MIN) + 1));
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