的preg_replace没有忽视[]从字符串

Question

这是我的代码：

$string = "Hello this is my text [readmore] and this is remaining text"; 
echo preg_replace("[readmore]","",$string); 

这是我预期输出：

Hello this is my text and this is remaining text 

这是我实际输出：

Hello this is my text [] and this is remaining text 

问题很简单如何获得乘坐“[]”也是？

Answer 1

您需要逃生[ & ]。尝试下面的正则表达式，

preg_replace("/\[([^\[\]]++|(?R))*+\]/", "", $string); 

OUTPUT：

Hello this is my text and this is remaining text 

CodePad Demo.

Answer 2

您需要转义括号才能在正则表达式中使用。另外，您可能需要查看preg_replace的手册，因为您忘记了/需要围绕您的正则表达式。

$string = "Hello this is my text [readmore] and this is remaining text"; 
echo preg_replace("/\[readmore\]/","",$string); 

Answer 3

逃离 '[' 和 ']' 字符：

这个脚本：

$string = "Hello this is my text [readmore] and this is remaining text"; 
echo preg_replace("[\\[readmore\\] ]","",$string); 

这个结果（我测试了这一点）：

Hello this is my text and this is remaining text  

Answer 4

使用str_replace

$string = "Hello this is my text [readmore] and this is remaining text"; 
echo str_replace("[readmore]","",$string); 

输出

Hello this is my text and this is remaining text