如何在爪哇形成钻石

Question

我想弄清楚为什么我的钻石并没有完全形成在底部。当用户输入任何大于三的奇数时，钻石在底部不能正确地形成（它仅在最大中线后面打印一行）。它看起来像这样（我想在这个例子中五行）：

* 
    * * 
    * * * 
    * * 

我相信有什么毛病了对于被认为创造了钻石底环。代码为：

//bottom of the diamond 
    for(j = (in + 1)/2; j < in; j++){ //similar to the first for statement instead when j equals the user's input plus one divided by two it will then go to the next for loop (the diamond starts to shrink) 
     for(i = 1; i < j; i++){ //when i equals one, and j is greater than one 
      System.out.print(" "); //prints space 
     } 
     for(l = 0; l < in - j; j++){ //similar to the for loop that prints the asterisk to the left this for loop goes through when l equals zero, and this time is less than the user's input minus j 
      System.out.print(" *"); //prints the bottom asterisks 
     } 
     System.out.println(""); //starts another blank new line 
    } //just like the top section it keeps looping until the requirements are no longer met 

我在做什么错了？

Answer 1

尽管Lashane在他的评论中指出了直接的问题，但我注意到你的逻辑比需要的更复杂。

所以，在回答你的问题

我在做什么错？

允许我提供一个较少混淆的实现，该实现使用相同的循环体代码钻石的顶部和底部。

int in = 5; 
for (int j = 1; j <= in; j++) { 
    for (int i = 0; i < in - j; i++) { 
    System.out.print(" "); 
    } 
    for (int i = 0; i < j; i++) { 
    System.out.print(" *"); 
    } 
    System.out.println(""); 
} 
for (int j = in - 1; j >= 1; j--) { 
    for (int i = 0; i < in - j; i++) { 
    System.out.print(" "); 
    } 
    for (int i = 0; i < j; i++) { 
    System.out.print(" *"); 
    } 
    System.out.println(""); 
} 

现在两个for环路之间的唯一区别是，第一计数了从1到in和第二计数回落从in - 1到1。