2013-03-05 84 views
0

我有这样一个时间戳:1362466800从现在开始转换Unix时间戳时间在PHP

我想它输出到这样的事情:

Time left: 1 Year 2 Months 5 Days 17 hours 6 Minutes Left

此外,如果有小于1年或不到1个月等。该部分字符串需要隐藏。

我知道有一些内置PHP函数这个在5.3+,但他们似乎并没有能够隐藏均为0

感谢任何帮助值。

+0

你可以使用DateTime类在PHP中,然后使用差异来获得差异。就隐藏而言,只要检查每一个是否为0,并且如果它不显示它。 – kennypu 2013-03-05 01:50:31

回答

4
$datetime1 = new DateTime(); 
$datetime2 = new DateTime('@1362466800'); 
$interval = $datetime1->diff($datetime2); 
$elapsed = $interval->format('%y years %m months %a days %h hours %i minutes %S seconds'); 
echo $elapsed; 

See it in action

编辑

如果你想elimate具有零个值,可以使用下面的代码片段删除他们的任何时期。

$empties = array('0 years', '0 months', '0 days', '0 hours', '0 minutes', '0 seconds'); 
echo str_replace($empties, '', $elapsed); 

参考

+0

如何让它隐藏0的项目?在你的例子中有0年,0个月和0天,但它们都仍然显示。 – Talon 2013-03-05 01:56:07

+0

这很好,认为这也没有得到单数和复数的正确(例如它表示'1天'而不是'1天'),并且最好只显示最外面的时间,所以如果有2天3小时45秒剩余我希望字符串只能说2天,如果还剩3小时25秒,我希望字符串只能说3小时。这种格式可以吗? – Talon 2013-03-05 02:06:06

+0

我不认为扩展这个代码来做到这一点会很困难。我提供的代码是最难的部分。 – 2013-03-05 02:08:06

0

基于@约翰德斯回答我能想出输出一个非常简单的阅读时间的函数从现在起显示:

function daysLeft($timestamp) { 
    $datetime1 = new DateTime('@'.time()); 
    $datetime2 = new DateTime('@' . $timestamp); 
    $interval = $datetime1->diff($datetime2); 

    $years = $interval->format('%y'); 
    $months = $interval->format('%m'); 
    $days = $interval->format('%a'); 
    $hours = $interval->format('%h'); 
    $minutes = $interval->format('%i'); 
    $seconds = $interval->format('%S'); 

    if($seconds): 
     $elapsed = $seconds == 1 ? $seconds . ' Second ' : $seconds . ' Seconds '; 
    endif; 
    if($minutes): 
     $elapsed = $minutes == 1 ? $minutes . ' Minute ' : $minutes . ' Minutes '; 
    endif; 
    if($hours): 
     $elapsed = $hours == 1 ? $hours . ' Hour ' : $hours . ' Hours '; 
    endif; 
    if($days): 
     $elapsed = $days == 1 ? $days . ' Day ' : $days . ' Days '; 
    endif; 
    if($months): 
     $elapsed = $months == 1 ? $months . ' Month ' : $months . ' Months '; 
    endif; 
    if($years): 
     $elapsed = $years == 1 ? $years . ' Year ' : $years . ' Years '; 
    endif; 

    return $elapsed; 
} 

如果有人试图做类似的事情。

0

基于@Talon我决定去远一点,写一个小类:

/** 
* Calculates the time between two UNIX timestamps 
* Like 3 hours or 180 minutes. 
* 
* @package Add Package Name Here 
* @version 1 
* @since Jul 12, 2013 
* @author Andrew Starlike <[email protected]> 
*/ 
class NiceDate 
{ 

private $translation; 

/** 
* @param array $translation 
*/ 
public function __construct($translation = null) 
{ 
$this->setTranslation($translation); 
} 

/** 
* Sets the translation of the time string 
* 
* @param array $translation (the array must have this keys 'second', 'minute', 'hour', 'day', 'month', 'year') 
*/ 
private function setTranslation($translation = null) 
{ 
if ($translation === null) { 
    $translation = array(); 
    $plural = 's'; 
    $formats = array('second', 'minute', 'hour', 'day', 'month', 'year'); 
    foreach ($formats as $format) { 
    $translation[$format] = ucfirst($format); 
    $translation[$format . $plural] = ucfirst($format . $plural); 
    } 
} 

$this->translation = $translation; 
} 

/** 
* 
* @param int $old (UNIX timestamp) 
* @param int $newer (UNIX timestamp) 
* @return string 
*/ 
public function timeLeft($old, $newer) 
{ 
$datetime1 = new DateTime('@' . $newer); 
$datetime2 = new DateTime('@' . $old); 
$interval = $datetime1->diff($datetime2); 

$years = $interval->format('%y'); 
$months = $interval->format('%m'); 
$days = $interval->format('%a'); 
$hours = $interval->format('%h'); 
$minutes = $interval->format('%i'); 
$seconds = $interval->format('%S'); 

$translation = $this->translation; 

if ($seconds): 
    $elapsed = $seconds . ' '; 
    $elapsed .= $seconds == 1 ? $translation['second'] : $translation['seconds']; 
endif; 
if ($minutes): 
    $elapsed = $minutes . ' '; 
    $elapsed .= $minutes == 1 ? $translation['minute'] : $translation['minutes']; 
endif; 
if ($hours): 
    $elapsed = $hours . ' '; 
    $elapsed .= $hours == 1 ? $translation['hour'] : $translation['hours']; 
endif; 
if ($days): 
    $elapsed = $days . ' '; 
    $elapsed .= $days == 1 ? $translation['day'] : $translation['days']; 
endif; 
if ($months): 
    $elapsed = $months . ' '; 
    $elapsed .= $months == 1 ? $translation['month'] : $translation['months']; 
endif; 
if ($years): 
    $elapsed = $years . ' '; 
    $elapsed .= $years == 1 ? $translation['year'] : $translation['years']; 
endif; 

return $elapsed; 
} 

} 
0

你可以这样说:

echo secondsToTime(1362466800); 

    function secondsToTime($seconds) { 
    $dtF = new \DateTime('@0'); 
    $dtT = new \DateTime("@$seconds"); 
    return $dtF->diff($dtT)->format('%a days, %h hours, %i minutes and %s seconds'); 
}