2016-11-11 145 views
1

对于iOS应用程序,我将一些Objective-C代码转换为Swift。在Swift中,如何配置AutoreleasingUnsafeMutablePointer?

Objective-C的代码使用的方法与此签名:

+ (nullable NSArray<MTKMesh*>*)newMeshesFromAsset:(nonnull MDLAsset *)asset 
     device:(nonnull id<MTLDevice>)device 
sourceMeshes:(NSArray<MDLMesh*>* __nullable * __nullable)sourceMeshes 
     error:(NSError * __nullable * __nullable)error; 

这里是它是如何叫:

NSArray<MTKMesh *> *mtkMeshes; 
NSArray<MDLMesh *> *mdlMeshes; 

mtkMeshes = [MTKMesh newMeshesFromAsset:asset 
           device:_device 
          sourceMeshes:&mdlMeshes 
            error:&error]; 

我试图将其转换为斯威夫特,我想我做错了,因为方法调用总是失败。

雨燕以上版本的方法:

open class func newMeshes(from asset: MDLAsset, device: MTLDevice, sourceMeshes: AutoreleasingUnsafeMutablePointer<NSArray?>?) throws -> [MTKMesh] 

我如何使用它:

do { 

    var myPointer: AutoreleasingUnsafeMutablePointer<NSArray?>? = nil 
    myPointer = AutoreleasingUnsafeMutablePointer<NSArray?>.init(&modelIOMeshList) 

    metalMeshList = try MTKMesh.newMeshes(from:asset, device:device, sourceMeshes: myPointer) 

} catch { 
    fatalError("Error: Can not create Metal mesh from Model I/O asset") 
} 

的方法应该是填充这两个数组。它不这样做。我在这里错过了什么?

回答

4

要类型的参数

AutoreleasingUnsafeMutablePointer<NSArray?>? 

你可以通过与&一个NSArray?变量的地址,所以这应该工作:

var sourceMeshes: NSArray? 
metalMeshList = try MTKMesh.newMeshes(from:asset, device:device, 
             sourceMeshes: &sourceMeshes) 
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