MySQL：查询优化

Question

SELECT a.FundIDRecv,a.SubscribeDt, b.FundName, 
(
    SELECT SUM(c.PricePerWeek) 
    FROM tbl_Hive c 
    WHERE c.FundID IN 
    (
     SELECT FundID from tbl_FundStatic 
     WHERE FundID IN 
     (
      SELECT FundIDSend 
      FROM tbl_FundSubscriptions 
      WHERE FundIDRecv = a.FundIDRecv 
      AND SubscribeDt >= subdate(CURDATE(), INTERVAL weekday(CURDATE()) DAY) 
     ) 
     AND UserID = '14' 
    ) 
) as Price 
FROM tbl_FundSubscriptions a, tbl_Hive b 
WHERE a.FundIDRecv = b.FundID 
AND a.SubscribeDt >= subdate(CURDATE(), INTERVAL weekday(CURDATE()) DAY) 
AND a.FundIDRecv IN 
(
    SELECT FundIDRecv 
    FROM tbl_FundSubscriptions 
    WHERE FundIDSend IN (
     SELECT FundID 
     FROM tbl_FundStatic 
     WHERE UserID = '14' 
    ) 
) 
GROUP BY FundIDRecv 

此查询需要大量时间来获取数据。

如何优化此查询以使其执行并获取结果的速度比它快？

Answer 1

用JOIN子句替换您的嵌套选择。借此例如：

AND a.FundIDRecv IN 
(
    SELECT FundIDRecv 
    FROM tbl_FundSubscriptions 
    WHERE FundIDSend IN (
     SELECT FundID 
     FROM tbl_FundStatic 
     WHERE UserID = '14' 
    ) 
) 

为什么不加入tbl_FundStatic像这样

FROM tbl_FundSubscriptions a 
JOIN tbl_FundStatic s ON (a.FundIDSend = s.FundID) 
WHERE s.UserID = '14' 

当然外部查询，我不知道这是否仍然是正确的，但它会给你一个主意。此外，您应该避免SELECT子句本身的嵌套选择。这是更好地从它

Answer 2

未经测试加入tbl_FundStatic然后选择字段，但是这会给你一展身手：

SELECT a.fundidrecv, 
     a.subscribedt, 
     b.fundname, 
     SUM(b.priceperweek) AS price 
FROM tbl_fundsubscriptions a 
     JOIN tbl_hive b 
     ON a.fundidrecv = b.fundid 
     JOIN tbl_fundsubscriptions fs 
     ON fs.fundidrecv = a.fundidrecv 
     JOIN tbl_fundstatic fst 
     ON fst.fundid = fs.fundidsend 
      AND fst.userid = '14' 
WHERE a.subscribedt >= SUBDATE(Curdate(), INTERVAL Weekday(Curdate()) DAY) 
GROUP BY a.fundidrecv 

您需要在以下几列添加索引：

• （一个。 fundidrecv，a.subscribedt）
• （b.fundid）
• （fs.fundidrecv）
• （fst.f undid，fst.userid）