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表上的用户列表和当前日志如何显示在用户位置
**Posts:**
| id | userID | title |
| 1 | 6 | text1 |
| 2 | 5 | text2 |
| 3 | 8 | text3 |
**Votes:**
| id | userID | postID |
| 1 | 6 | 2 |
| 2 | 5 | 2 |
| 3 | 8 | 1 |
| 4 | 8 | 3 |
| 5 | 8 | 2 |
**Sql**
SELECT p.*,(SELECT count(*) FROM votes AS v WHERE v.postID=p.id AS count)
FROM posts AS p WHERE p.userID = 6
ORDRER BY count DESC
这将使全球3大名单,但我想在上面,如果在列表中有类似
Your position is 3
如果用户登录。如何计算用户位置?基地他的信息发表多少票有
这给出了一个语法错误 – 2012-07-12 17:20:22
什么错误? – 2012-07-12 17:40:33
为正确的语法使用附近'ORDER BY count DESC)作为temp_p WHERE p.iduser = 39'在第13行 – 2012-07-12 17:55:39