Mysql：检查用户是否在过去的14,60或120天内没有登录

Question

试图建立一个系统，检查巫婆用户在过去的14,60或120天内没有登录过。如果用户未在14天内登录但是同时向该用户发送电子邮件60天和120天，我想发送电子邮件。

表：user_counts user_count当天有超过80 000行。

柱：时间日期时间在MySQL

// Number of days a user have not been login 
$dateCheck = array('14', '60', '120'); 

foreach ($dateCheck as $day) {   

    $userList = $wpdb->get_results(' 
    SELECT id, user_id 
    FROM user_counts 

    WHERE DATE(time) = "'.date("Y-m-d", strtotime("-".$day." day")).'" 
     AND time != (
      SELECT MAX(time) FROM user_counts 
      WHERE time < DATE_SUB(NOW(), INTERVAL '.$day.' DAY) 
    ) 
    GROUP BY user_id 
    '); 

} 

结果 我得到了所有的14,60及120天同一USER_ID。

Answer 1

// Number of days a user have not been login 
$dateCheck = array('14', '60', '160'); 

$res = $wpdb->get_results(' 
    SELECT id, user_id, MAX(DATE(time)) as t 
    FROM user_counts  
    GROUP BY user_id 
    HAVING t <= "'.date("Y-m-d", strtotime("-".min($dateCheck)." day")).'" 
    ORDER BY t 
'); 

rsort($dateCheck); 
foreach ($res as $result) { 
    $date = date_create($res); 

    foreach ($dateCheck as $day) { 

     if ($result->t == date("Y-m-d", strtotime("-".$day." day"))) { 

      // Send for exempel a mail 
      // check witch email temple to use by using: $day 

     } 
    } 
}