MySQL查询（下同）将返回不同的结果集

Question

我天真到MySQL世界.... :)我试图使用连接表来查询不同的结果顺序，

在那里我遇到了一个问题与结果集...并表的结构是为

下面

...

VIDEO_XXXXX 

| Field   | Type   | Null | Key | Default   | Extra      | 
| VIDEO_ID  | int(255)   
| TAG_NAME  | varchar(1000) 
| SHOP_ID  | varchar(100) FK 
| LOVES   | int(255)  
| VIDEO_URL  | varchar(1000) 
| UPLOADED_DATE | 


PLACE_TABLE... 

SHOP_ID  | varchar(100) PK 

查询貌似..

SELECT V.SHOP_ID 
    FROM VIDEO_xxxx V 
    JOIN STUB_xxxx_TABLE S ON S.SHOP_ID=V.SHOP_ID 
    WHERE S.COUPON_STATUS='REDEEMED' 
GROUP BY V.SHOP_ID 
ORDER BY COUNT(S.COUPON_GENERATED_ID) DESC; 

结果设置如下......

+-----------+ 
| SHOP_ID | 
+-----------+ 
| 001  | 
| 004  | 
| 005  | 
| 003  | 
| 002  | 

第二个查询是....

SELECT V.SHOP_ID 
    FROM SECOND_TABLE V 
    JOIN STUB_xxxx_TABLE S ON S.SHOP_ID=V.SHOP_ID 
    WHERE S.COUPON_STATUS='REDEEMED' 
GROUP BY V.SHOP_ID 
ORDER BY COUNT(S.COUPON_GENERATED_ID) DESC; 

而且结果集...

+--------+ 
| SHOP_ID| 
+--------+ 
|001  | 
|004  | 
|003  | 
|002  | 
005  | 

我不知道为什么order_shop_id洗牌.... :(:(任何帮助将不胜感激... :)，

Answer 1

您可以添加表达式COUNT(S.COUPON_GENERATED_ID) where子句：

SELECT V.SHOP_ID,COUNT(S.COUPON_GENERATED_ID) 
    FROM SECOND_TABLE V 
    JOIN STUB_xxxx_TABLE S ON S.SHOP_ID=V.SHOP_ID 
    WHERE S.COUPON_STATUS='REDEEMED' 
GROUP BY V.SHOP_ID 
ORDER BY COUNT(S.COUPON_GENERATED_ID) DESC; 

如果你不想在这个结果额外的价值，你可以使用子查询：

SELECT SHOP_ID 
    FROM (
      SELECT V.SHOP_ID,COUNT(S.COUPON_GENERATED_ID) AS CNT 
      FROM SECOND_TABLE V 
      JOIN STUB_xxxx_TABLE S ON S.SHOP_ID=V.SHOP_ID 
      WHERE S.COUPON_STATUS='REDEEMED' 
     GROUP BY V.SHOP_ID 
     ) 
ORDER BY CNT DESC