2016-01-06 45 views
-1

我在我的应用程序图标上添加了3D Touch以显示快速操作菜单。我想我应该把它设置正确。使用QuickActionItems时iPhone会冻结

问题是,当我选择快速操作菜单中的某个项目时,iPhone在打开应用程序之前冻结了几秒钟。

这是我AppDelegate.swift

import UIKit 
import Parse 


@available(iOS 9.0, *) 
@UIApplicationMain 
class AppDelegate: UIResponder, UIApplicationDelegate { 

    var window: UIWindow? 

    func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool { 
     // Override point for customization after application launch. 

     Parse.setApplicationId("xx", 
      clientKey: "xx") 

     let currentInstallation: PFInstallation = PFInstallation.currentInstallation() 
     currentInstallation.badge = 0 
     currentInstallation.saveEventually() 

     return true 
    } 

    func applicationWillResignActive(application: UIApplication) { 
     // Sent when the application is about to move from active to inactive state. This can occur for certain types of temporary interruptions (such as an incoming phone call or SMS message) or when the user quits the application and it begins the transition to the background state. 
     // Use this method to pause ongoing tasks, disable timers, and throttle down OpenGL ES frame rates. Games should use this method to pause the game. 
    } 

    func applicationDidEnterBackground(application: UIApplication) { 
     // Use this method to release shared resources, save user data, invalidate timers, and store enough application state information to restore your application to its current state in case it is terminated later. 
     // If your application supports background execution, this method is called instead of applicationWillTerminate: when the user quits. 
    } 

    func applicationWillEnterForeground(application: UIApplication) { 
     // Called as part of the transition from the background to the active state; here you can undo many of the changes made on entering the background. 
    } 

    func applicationDidBecomeActive(application: UIApplication) { 
     // Restart any tasks that were paused (or not yet started) while the application was inactive. If the application was previously in the background, optionally refresh the user interface. 
    } 

    func applicationWillTerminate(application: UIApplication) { 
     // Called when the application is about to terminate. Save data if appropriate. See also applicationDidEnterBackground:. 
    } 

    func application(application: UIApplication, performActionForShortcutItem shortcutItem: UIApplicationShortcutItem, completionHandler: (Bool) -> Void) { 

     let rootNavigationViewController = window!.rootViewController as? UINavigationController 
     let rootViewController = rootNavigationViewController?.viewControllers.first as UIViewController? 

     rootNavigationViewController?.popToRootViewControllerAnimated(false) 

     if shortcutItem.type == "JEGHARALDRI" { 
      rootViewController?.performSegueWithIdentifier("JEGHARALDRISEGUE", sender: nil) 
     } 
     if shortcutItem.type == "PLING" { 
      rootViewController?.performSegueWithIdentifier("PLINGSEGUE", sender: nil) 
     } 
     if shortcutItem.type == "FLASKETUTENPEKERPÅ" { 
      rootViewController?.performSegueWithIdentifier("FLASKETUTENPEKERPÅSEGUE", sender: nil) 
     } 
     if shortcutItem.type == "KORTETTALER" { 
      rootViewController?.performSegueWithIdentifier("KORTETTALERSEGUE", sender: nil) 
     } 
    } 
} 
+0

你如何处理它?看起来像是崩溃了,因为应用程序不知道该显示什么 –

+0

@QuentinRibierre好吧,它不会崩溃。我展示了我该怎么做,但问题是iPhone在打开应用程序之前冻结了几秒钟。 –

回答

1

我觉得你的应用程序代理应该更貌似是这样的

import UIKit 

@UIApplicationMain 
class AppDelegate: UIResponder, UIApplicationDelegate { 

    //MARK: - Properties 

    var window: UIWindow? 

    lazy var quickActionManager: QuickActionsManager = { 
     return QuickActionsManager() 
    }() 

    //MARK: - AppDelegate Methods 

    func application(application: UIApplication, 
     didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool 
    { 
     return self.setupQuickActions(launchOptions) 
    } 

    func application(application: UIApplication, performActionForShortcutItem 
     shortcutItem: UIApplicationShortcutItem, completionHandler: (Bool) -> Void) 
    { 
     completionHandler(self.quickActionManager.handleShortcut(shortcutItem)) 
    } 

    //MARK: - Private Methods 

    private func setupQuickActions(launchOptions: [NSObject: AnyObject]?) -> Bool 
    { 
     guard let shortcutItem = launchOptions?[UIApplicationLaunchOptionsShortcutItemKey] 
     as? UIApplicationShortcutItem else { return false } 
     return self.quickActionManager.handleShortcut(shortcutItem) 
    } 
} 

所以,你得到所有的逻辑来处理一个快速行动的快速行动经理,看起来像这样

//MARK: - Public Methods 

    func handleShortcut(shortcut: UIApplicationShortcutItem?) -> Bool 
    { 
     guard let shortcut = shortcut else { return false } 
     // Get the key of the shortcutItem 
     let key = self.shortKeyForType(shortcut.type) 
     // Check if that key is the key of a knowed viewController 
     guard let viewControllerKey = ViewControllerKeys(rawValue: key) else { return false } 
     // Try to show This View Controller 
     return self.showViewController(viewControllerKey) 
    } 

假设你有一个viewController枚举来显示匹配的每个快速操作。

我希望这回答你的问题,让我知道如果你有更多。

+0

谢谢!但是最后的代码给了我两个错误:http://s11.postimg.org/sqn14qpsj/Screen_Shot_2016_01_08_at_16_11_57.png –