分析JSON与json.net但蹊跷的猜测

Question

http://api.openweathermap.org/data/2.5/weather?q=Ankara,tr这是当前的JSON数据，首先我用JSON 2 C＃创建它，我得到这个

using System; 
using System.Collections.Generic; 

namespace weatherSample 
{ 
    public class service 
    { 
     public service() 
     { 
     } 
    } 

    public class Coord 
    { 
     public double lon { get; set; } 

     public double lat { get; set; } 
    } 

    public class Sys 
    { 
     public int type { get; set; } 

     public int id { get; set; } 

     public double message { get; set; } 

     public string country { get; set; } 

     public int sunrise { get; set; } 

     public int sunset { get; set; } 
    } 

    public class Weather 
    { 
     public int id { get; set; } 

     public string main { get; set; } 

     public string description { get; set; } 

     public string icon { get; set; } 
    } 

    public class MainWeather 
    { 
     public double temp { get; set; } 

     public int pressure { get; set; } 

     public int humidity { get; set; } 

     public double temp_min { get; set; } 

     public double temp_max { get; set; } 
    } 

    public class Wind 
    { 
     public double speed { get; set; } 

     public int deg { get; set; } 
    } 

    public class Clouds 
    { 
     public int all { get; set; } 
    } 

    public class RootObject 
    { 
     public Coord coord { get; set; } 

     public Sys sys { get; set; } 

     public List<Weather> weather { get; set; } 

     public string @base { get; set; } 

     public MainWeather main { get; set; } 

     public Wind wind { get; set; } 

     public Clouds clouds { get; set; } 

     public int dt { get; set; } 

     public int id { get; set; } 

     public string name { get; set; } 

     public int cod { get; set; } 
    } 
} 

现在我试图解析，但我得到了一些麻烦，

WebClient webC = new WebClient (link); 

var jsonDatas = JObject.Parse (y); 

var c = JsonConvert.DeserializeObject <MainWeather> (y); 

Console.Write (c.temp); 

则返回0值

应该是什么问题？

Answer 1

你需要反序列化到的RootObject一个实例，而不是：

RootObject result = JsonConvert.DeserializeObject<RootObject>(y); 

然后访问MainWeather属性：

Console.Write(result.main.temp); 

例子：https://dotnetfiddle.net/LWfHrH

如果你只是关心MainWeather对象，你也可以这样做：

MainWeather r = JObject.Parse(y)["main"].ToObject<MainWeather>();