所以我目前的任务是做一个基本的猎人与猎物的模拟,以及具有其它几个问题后,我的教授建议,我只是把一切都放在main.cpp
实际得到的现在工作的东西。“无效使用不完全类型的”
我目前的问题是,在Creature::Find()
函数声称Grid
类是不完整的,即使它是预先声明在文件的顶部。我最初的想法是在Creature
之前放置Grid
类,但这会导致更多或相同的错误(指Creature
不完整),因为Grid
本质上是指针的二维数组。下面是代码的相关位,整个文件可以在Dropbox here上找到。
class Grid; //*** error: forward declaration of 'class Grid'
//Other stuff...
class Creature
{
public:
Grid* theGrid;
Coords position;
int stepBreed;
int stepHunger;
char face;
bool hasMoved;
Creature(Grid* _grid, Coords _position, char _face) //Constructor
{
theGrid = _grid;
position = _position;
face = _face;
stepBreed = stepHunger = 0;
hasMoved = false;
}
vector<Coords> Find(char thisFace) //Returns a list of coords with prey on them
{
vector<Coords> result;
for(int i = position.x-1; i <= position.x+1; i++)
for(int j = position.y-1; j <= position.y+1; j++)
{
Coords temp(i,j);
if(theGrid->Occupant(temp) == thisFace) //*** error: invalid use of incomplete type 'class Grid'
result.push_back(temp);
}
return result;
}
virtual Coords Move() = 0; //Allows the creature type to define it's own movement
virtual Coords Breed() = 0; //Allows the creature type to define it's own breeding
virtual bool Starve() = 0; //Allows the creature type to starve of its own accord
};
class Grid
{
public:
Creature* grid[MAX_X][MAX_Y];
Grid() //Initalizes the grid and spawns random creatures
{
cout<<endl<<"grid init"<<endl;
for(int i = 0; i < MAX_X; i++)
for(int j = 0; j < MAX_Y; j++)
grid[i][j] = NULL;
}
void Move() //Tells each creature on the grid to move
{
cout<<endl<<"--- Grid::Move() TOP ---"<<endl<<endl;
ResetMoved();
for(int i = 0; i < MAX_X; i++)
for(int j = 0; j < MAX_Y; j++)
if(grid[i][j])
grid[i][j]->Move();
cout<<endl<<"--- Grid::Move() BOTTOM ---"<<endl<<endl;
}
void Breed() //Tells each creature to breed (if it can)
{
}
void Kill() //Tells each creature to die (if it's old)
{
}
char** Snapshot() //Creates a char array "snapshot" of the board
{
char** result = new char*[MAX_X];
for(int i = 0; i < MAX_X; i++)
{
result[i] = new char[MAX_Y];
for(int j = 0; j < MAX_Y; j++)
{
result[i][j] = Occupant(Coords(i, j));
}
}
return result;
}
Creature* Get(Coords here) //Returns a pointer to the object at the specified position
{
return grid[here.x][here.y];
}
char Occupant(Coords here) //Returns the character of the specified position
{
if(!Get(here))
return FACE_EMPTY;
return Get(here)->face;
}
void Clear(Coords here) //Deletes the object at the specified position
{
cout<<endl<<"--- Grid::Clear() TOP ---"<<endl<<endl;
if(!Get(here))
{
cout<<" inside if"<<endl;
delete Get(here);
}
cout<<" outside if"<<endl;
grid[here.x][here.y] = NULL;
cout<<endl<<"--- Grid::Clear() BOTTOM ---"<<endl<<endl;
}
void ResetMoved()
{
for(int i = 0; i < MAX_X; i++)
for(int j = 0; j < MAX_Y; j++)
if(grid[i][j])
grid[i][j]->hasMoved = false;
}
};
编辑:预览和标记工具栏不工作的一些原因。
呀,抱歉关于制造新的问题类似的主题,就是不知道这是否必要了。我在各种职能上得到了未解决的外部问题,教授也无法弄清楚为什么要这样做,这就是为什么他让我把所有的东西都放在主体中。我认为Grid的预先声明是为了防止这样的东西,还是只适用于定义? – Farlo 2013-04-20 06:56:21
@Farlo不,预申报(通常称为正向声明)告诉编译器,电网是一个类,所以(例如)'电网* theGrid;'是合法的。但是前向声明并没有告诉编译器关于类的任何事情。所以'theGrid->乘员(临时)'是不合法的,甚至向前声明之后,因为前声明不告诉网格有一个名为乘员 – john 2013-04-20 06:58:54
方法@Farlo你通常可以通过确保*实现避免的一个问题,编译器*任何使用不完整类型的代码都遵循完成类型的声明。在这种情况下,没有任何东西可以阻止你在课堂之外移动执行'Creature :: Find'方法(只是将它声明为一个成员,不要在类中实现)并且在*正式'Grid'的定义。并在答案+1。 – WhozCraig 2013-04-20 07:00:59