派生表中没有指定列号的列名称

Question

我收到此错误消息，有人可以建议解决方案吗？

我已经看过了这个论坛，并不能找到一个解决方案

动态SQL错误
SQL错误代码= -104

对于没有指定列名无效的命令列表编号1 ACCRG

SELECT DISTINCT locationgroup.name AS MainGroup, product.num AS ProductNumber, 
    product.description AS ProductDescription, uom.code AS UOM, company.name AS company, 
    sum(((SELECT SUM(productsSold.qtyfulfilled) FROM soitem productsSold WHERE soitem.id = productsSold.id AND productsSold.productid = product.id) * COALESCE(uomconversion.multiply,1))/COALESCE(uomconversion.factor,1)) AS uomqty 

FROM soitem 
    LEFT OUTER JOIN so ON (so.id = soitem.soid) 
    LEFT OUTER JOIN product ON (soitem.productid = product.id) 
    LEFT OUTER JOIN uom ON (product.uomid = uom.id) 
    LEFT OUTER JOIN locationgroup ON (so.locationgroupid = locationgroup.id) 
    LEFT OUTER JOIN qbclass ON (qbclass.id = soitem.qbclassid) 
    LEFT OUTER JOIN customer ON (customer.id = so.customerid) 
    LEFT JOIN (SELECT max(accountgrouprelation.id) AS relationID, accountgrouprelation.accountid 
         FROM accountgrouprelation 
      LEFT JOIN accountGroup ON accountGroupRelation.groupId = accountGroup.id 
      WHERE UPPER(COALESCE (accountgroup.name, '%')) LIKE UPPER('%') 
         GROUP BY 2) accrg ON customer.accountid = accrg.accountid 
    LEFT JOIN accountgrouprelation ON accrg.relationid = accountgrouprelation.id 
    LEFT OUTER JOIN accountgroup ON (accountgroup.id = accountgrouprelation.groupid) 
    LEFT OUTER JOIN uomconversion ON ((product.uomid = uomconversion.touomid) AND (soitem.uomid = uomconversion.fromuomid)) 
    JOIN company ON company.id = 1 

WHERE soitem.qtyfulfilled > 0 
    AND soitem.typeid in (10,12,80) 
    AND locationgroup.id IN (1,2,3,4) 
    AND qbclass.id LIKE '%' 
    AND UPPER(so.salesman) LIKE UPPER('%') 
    AND UPPER(COALESCE (accountgroup.name, '%')) LIKE UPPER('%') 
    AND soitem.datelastfulfillment BETWEEN '2015-11-30 23:59:59.0' AND '2015-12-31 23:59:59.0' 
GROUP BY maingroup, productnumber, productdescription, uom, company 
ORDER BY 1,product.num ASCENDING 

Answer 1

不管你信不信，我认为错误是从你的ORDER BY声明来：

ORDER BY 1,product.num ASCENDING 

我不相信这是合法的ORDER BY MySQL中的常数。告诉错误，看起来MySQL正试图在ACCRG派生表中找到名为1的列。没有这样的列存在，因此你得到这个错误。相反，为什么不只是ORDER BY的产品编号？：

ORDER BY product.num ASCENDING