SQLite累计总和排序

Question

我正在寻找2个累计总和和按日期排序之间的差异，但日期列是在不同的表上，似乎是导致问题的日期。 （date位于eventinfo表中，我想使用的列位于results表中）。

我想要获得results.prize和results.totalbuyin之间的差异总计，其中results.event=eventinfo.eventname的总订购量为eventinfo.date。我还想过滤查询results.playername，这样我就可以获得任何单个玩家的总分。我能得到的日期栏出现在查询和订单日期，但总额在的ID号的顺序发生：

结果表

ID;PlayerName;TotalBuyIn;Prize;Rebuys;Event; 
1;Ole Schemion;100000;1062785;0;Aria $100K July 2014; 
2;Isaac Haxton;100000;813394;0;Aria $100K July 2014; 
3;Daniel Colman;100000;796821;0;Aria $100K July 2014; 
4;Daniel Cates;100000;297000;0;Aria $100K July 2014; 
5;Cary Katz;100000;0;0;Aria $100K July 2014; 

EventInfo表

ID;EventName;Date;Location;Country;PokerTour;UniquePlayers;Rebuys; 
1;ACOP 500k 2014;2014-11-01;City of Dreams;Macau;APPT;52;50; 
2;ACOP Super High Roller 2015;2015-11-13;City of Dreams;Macau;APPT;34;17; 
3;Alpha 8 Florida 2013;2013-08-26;Seminole Hard Rock;USA;WPT;18;3; 
4;Alpha 8 Florida 2015;2015-01-17;Seminole Hard Rock;USA;WPT;6;0; 
5;Aria $100K July 2014;2014-02-14;Emperor Palace;South Africa;WPT;9;1; 

在这些表results.event=eventinfo.eventname

失败的查询

SELECT t1.id, 
    t1.prize, 
    t1.TotalBuyIn, 
    t1.PlayerName, 
    (SUM(t2.prize)) - (SUM(t2.totalbuyin)), 
    eventinfo.Date 
FROM results t1 
INNER JOIN results t2 ON t1.id >= t2.id and t2.PlayerName = "Erik Seidel" 
INNER JOIN eventinfo ON t1.Event = eventinfo.EventName 
Where t1.PlayerName = "Erik Seidel" 
GROUP BY t1.id 
ORDER BY eventinfo.Date 

电流输出

t1.id;t1.prize;t1.TotalBuyIn;t1.PlayerName;(SUM(t2.prize)) - (SUM(t2.totalbuyin));eventinfo.Date; 
1314;618139;98902;Erik Seidel;135685;2011-01-22; 
1292;2472555;247255;Erik Seidel;-383552;2011-01-27; 
1401;1092780;100000;Erik Seidel;1128465;2011-05-18; 
1425;0;100000;Erik Seidel;1028465;2011-12-09; 
1127;0;100000;Erik Seidel;-2341985;2012-01-05; 

8号线是明显的问题，但我似乎无法重写代码来修复它。尽管我认为我已经加入了表格，但输入t1.date>=t2.date将不起作用。如果这有所作为，我正在使用SQLite3。

Answer 1

我会创造这样的第一个查询：

SELECT Date, EventName, (SUM(Prize)) - (SUM(TotalBuyIn)) AS Net 
FROM results 
INNER JOIN eventinfo ON Event = EventName 
GROUP BY Date, EventName 
ORDER BY eventinfo.Date 

我会创造这样的第二个查询：

SELECT PlayerName, (SUM(Prize) - SUM(TotalBuyIn)) AS Net, Date, EventName 
FROM Results 
INNER JOIN EventInfo ON Event = EventName 
GROUP BY PlayerName 
ORDER BY Date 

这里有个小技巧： 您创建了一个整数主键（ID ）在EventInfo表中，最好在结果表的Event列中使用这些整数值。使用文本值将表连接在一起会产生不必要的麻烦。

更新： 以下解决方案仅适用于一名玩家，但您已在示例中指定了特定玩家，所以我相信这就是您正在寻找的。

CREATE TEMPORARY TABLE TEMP AS SELECT Date, PlayerName, Prize, TotalBuyIn, SUM(t1.Prize - T1.TotalBuyIn) AS Net 
FROM Results t1 
INNER JOIN EventInfo t3 ON t1.Event = t3.EventName 
GROUP BY t1.PlayerName, t3.Date; 

SELECT Date, PlayerName, Prize, TotalBuyIn, 
(SELECT SUM(Net) FROM TEMP t2 WHERE t1.Date >= t2.Date AND PlayerName='Erik Seidel') AS Net 
FROM TEMP t1 
WHERE PlayerName='Erik Seidel' 
GROUP BY Date 
ORDER BY Date; 

DROP TABLE TEMP;