sql查询再次销售汇总

Question

这个问题是基于从另一个SO question, can be found here得到的答案。

我已成功地编写一个查询自己基于答案只要

Select s.pName, 
     s.ProductCode, 
     min(s.Price)       as MinPrice, 
     sum(s.Quantity)      as SalesQty, 
     sum(s.Price * s.Quantity)   as SalesValue, 
     isnull((select sum(Quantity) 
       from Breakages 
       where pGroup = 16 
         and quantity > 0), 0) as BreakQty, 
     isnull((select sum(Price * Quantity) 
       from Breakages 
       where pGroup = 16), 0)  as BreakValue, 
     isnull((select CASE 
         WHEN min(r.Quantity) != 0 THEN Sum(r.Quantity) 
         END), 0)    as ReturnQty, 
     isnull((select sum(Price * Quantity) 
       from SalesReturn 
       where pGroup = 16), 0)  as ReturnValue 
from SalesLog as s 
     INNER JOIN SalesReturn as r 
     ON r.BillDate = s.BillDate 
     INNER JOIN Breakages as b 
     ON r.BillDate = b.BillDate 
where s.BillDate = '12-10-2010' 
     and r.BillDate = '12-10-2010' 
     and b.BillDate = '12-10-2010' 
     and s.pGroup = 16 
     and b.pGroup = 16 
     and r.pGroup = 16 
group by s.pName, 
      s.ProductCode; 

这里是上述查询的输出

Name    Code Price SalesQty SValue BreakQty BValue RefundQty RQty 
CDM 42GRMS.  854 15  3  45  2  0   3  30 
APPLE JUICE 750ML 860 59  5  295  2  0   3  30 
BISLERI WATER  865  3  5  15  2  0   3  30 
PERK 35 GRMS  870 10  20  200  2  0   3  30 

有一个与输出一个问题，因为你可能不会得到，Code = 865的破损率为2，870的Refund为3，但所有的行都有破损和退款。

你可以在我的查询中找到实验。 感谢........等待回复来回

SalesRetrun表

CREATE TABLE [dbo].[SalesReturn](
    [srID] [int] IDENTITY(1,1) NOT NULL, 
    [ProductCode] [int] NULL, 
    [Quantity] [int] NULL, 
    [pGroup] [int] NULL, 
    [MemoNo] [int] NULL, 
    [SalesmanID] [int] NULL, 
    [Price] [int] NULL, 
    [BillDate] [nchar](10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL, 
    [AddedOn] [datetime] NULL, 
CONSTRAINT [PK_SalesReturn] PRIMARY KEY CLUSTERED 
([srID] ASC) WITH (PAD_INDEX = OFF, IGNORE_DUP_KEY = OFF) ON [PRIMARY] 
) ON [PRIMARY] 

SalesLog表

CREATE TABLE [dbo].[SalesLog](
    [SalesID] [int] IDENTITY(1,1) NOT NULL, 
    [MemoNo] [int] NULL, 
    [ProductCode] [int] NULL, 
    [Quantity] [int] NULL, 
    [Price] [int] NULL, 
    [pGroup] [int] NULL, 
    [pName] [nvarchar](30) COLLATE SQL_Latin1_General_CP1_CI_AS NULL, 
    [pSize] [int] NULL, 
    [BillDate] [nchar](10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL, 
CONSTRAINT [PK_SalesLog] PRIMARY KEY CLUSTERED 
( [SalesID] ASC)WITH (PAD_INDEX = OFF, IGNORE_DUP_KEY = OFF) ON [PRIMARY] 
) ON [PRIMARY] 

表破坏发生

CREATE TABLE [dbo].[Breakages](
    [breakId] [int] IDENTITY(1,1) NOT NULL, 
    [MemoNo] [int] NULL, 
    [SalesmanID] [int] NULL, 
    [ProductCode] [int] NULL, 
    [pName] [nvarchar](30) COLLATE SQL_Latin1_General_CP1_CI_AS NULL, 
    [Quantity] [int] NULL, 
    [Price] [int] NULL, 
    [pGroup] [int] NULL, 
    [BillDate] [nchar](10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL, 
    [AddedOn] [datetime] NULL, 
CONSTRAINT [PK_Breakages_1] PRIMARY KEY CLUSTERED (
[breakId] ASC)WITH (PAD_INDEX = OFF, IGNORE_DUP_KEY = OFF) ON [PRIMARY] 
) ON [PRIMARY] 

更新的查询
我添加Products表参考，并呈现出所需的输出，但其显示所有产品是否有任何出售或断裂或发生退款或没有在该日期。

我不想在没有销售或没有损坏或没有退款的情况下显示行。这会减少我的报告大小。当前显示319行，但删除行（手动计算）后，根据我的逻辑它减少到16行（在假数据）

SELECT p.pName, p.pCode, MIN(p.pPrice) AS MinPrice 
    , SUM(s.Quantity) AS SalesQty, SUM(s.Quantity) * MIN(p.pPrice) AS SalesValue 
    , MIN(b.Quantity) AS BreakQty, MIN(b.Quantity) * MIN(p.pPrice) AS BreakValue 
    , MIN(r.Quantity) AS ReturnQty, MIN(r.Quantity) * MIN(p.pPrice) AS ReturnValue 
FROM Products AS p 

OUTER APPLY (SELECT SUM(s.Quantity) AS Quantity 
     FROM SalesLog AS s 
     WHERE s.BillDate = '12-10-2010' 
       AND s.ProductCode = p.pCode 
     ) AS s 
OUTER APPLY (SELECT SUM(r.Quantity) AS Quantity 
     FROM SalesReturn AS r 
     WHERE r.BillDate = '12-10-2010' 
       AND r.ProductCode = p.pCode 
     ) AS r 
OUTER APPLY (SELECT SUM(b.Quantity) AS Quantity 
     FROM Breakages AS b 
     WHERE b.BillDate = '12-10-2010' 
       AND b.ProductCode = p.pCode 
     ) AS b 
WHERE p.pGroup!=15 and p.pGroup!=16 
GROUP BY p.pName, p.pCode; 

Answer 1

你正在移动的目标职位！但是，以下是您更新问题的可能解决方案。

注：

1. 这是更有效的使用>或<代替=如果你能！这就是为什么我改变了p.pGroup上的谓词。 （我假设没有15至16岁的小组）。
2. 所有灌溉都是在APPLY子查询中完成的，因此您不需要再使用GROUP BY子句。

这里是更新查询：

SELECT p.pName 
     , p.ProductCode 
     , p.Price AS MinPrice 
     , s.Quantity AS SalesQty 
     , s.Quantity * p.Price AS SalesValue 
     , b.Quantity AS BreakQty 
     , b.Quantity * p.Price AS BreakValue 
     , r.Quantity AS ReturnQty 
     , r.Quantity * p.Price AS ReturnValue 
FROM Products AS p 
OUTER APPLY (SELECT SUM(s.Quantity) AS Quantity 
      FROM SalesLog AS s 
      WHERE s.BillDate = '12-10 2010' 
        AND s.ProductCode = p.ProductCode 
      ) AS s 
OUTER APPLY (SELECT SUM(r.Quantity) AS Quantity 
      FROM SalesReturn AS r 
      WHERE r.BillDate = '12-10 2010' 
        AND r.ProductCode = p.ProductCode 
      ) AS r 
OUTER APPLY (SELECT SUM(b.Quantity) AS Quantity 
      FROM Breakages AS b 
      WHERE b.BillDate = '12-10 2010' 
        AND b.ProductCode = p.ProductCode 
      ) AS b 
WHERE p.pGroup < 15 
     AND p.pGroup > 16 
     AND (
      s.Quantity IS NOT NULL 
      OR r.Quantity IS NOT NULL 
      OR b.Quantity IS NOT NULL 
      ) 

Answer 2

你的子查询，如此，将总是得到相同的数据的每一行，因为where子句不引用外部查询中的任何内容。

isnull((select sum(Quantity) 
      from Breakages 
      where pGroup = 16 
        and quantity > 0), 0) as BreakQty 

我没有时间弄清楚它应该是什么。

Answer 3

子查询应该使用where子句引用主查询。将te sum与SalesLog.ProductCode关联起来，我想。为了更准确的答案，你应该发布表结构。

Answer 4

由于我不知道您的数据，因此很难给出准确的答案。但是，我认为你是在沿着这条路线：

SELECT s.pName 
     , s.ProductCode 
     , MIN(s.Price) AS MinPrice 
     , SUM(s.Quantity) AS SalesQty 
     , SUM(s.Quantity) * MIN(s.Price) AS SalesValue 
     , MIN(b.Quantity) AS BreakQty 
     , MIN(b.Quantity) * MIN(s.Price) AS BreakValue 
     , MIN(r.Quantity) AS ReturnQty 
     , MIN(r.Quantity) * MIN(s.Price) AS ReturnValue 
FROM SalesLog AS s 
OUTER APPLY (SELECT SUM(r.Quantity) AS Quantity 
      FROM @SalesReturn AS r 
      WHERE r.BillDate = s.BillDate 
        AND r.ProductCode = s.ProductCode 
      ) AS r 
OUTER APPLY (SELECT SUM(b.Quantity) AS Quantity 
      FROM @Breakages AS b 
      WHERE b.BillDate = s.BillDate 
        AND b.ProductCode = s.ProductCode 
      ) AS b 
WHERE s.BillDate = '12-10 2010' 
GROUP BY s.pName 
     , s.ProductCode ;