2017-06-16 61 views

回答

1

您可以LEAD提供的版本,你都在支持它这样做。

select customer,orderdate,item, 
lead(orderdate,1) over(partition by customer order by date) as second_date, 
lead(item,1) over(partition by customer order by date) as second_item, 
lead(orderdate,2) over(partition by customer order by date) as third_date, 
lead(item,2) over(partition by customer order by date) as third_item 
from tbl 
+0

谢谢。这部分帮助我。 –

+0

你应该发表另一个问题..而不是在接受答案后改变问题。 –

+0

谢谢。我是这个论坛的新手。 –

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