我想要创建一个通用函数来根据传递的属性对类的数组进行排序。按属性排序类的数组的通用函数
例如,我有这些类
public class Car {
var id: Int
var manufacturer: String
var variant: String
init(id: Int, manufacturer: String, variant: String) {
self.id = id
self.manufacturer = manufacturer
self.variant = variant
}
}
enum Gender {
case male
case female
}
public class Person {
var id: Int
var name: String
var age: Int
var gender: Gender
init(id: Int, name: String, age: Int, gender: Gender) {
self.id = id
self.name = name
self.age = age
self.gender = gender
}
}
而且这些阵列,
let cars = [
Car(id: 1, manufacturer: "Ford", variant: "Focus"),
Car(id: 2, manufacturer: "Nissan", variant: "Skyline"),
Car(id: 3, manufacturer: "Dodge", variant: "Charger"),
Car(id: 4, manufacturer: "Chevrolet", variant: "Camaro"),
Car(id: 5, manufacturer: "Ford", variant: "Shelby")
]
let persons = [
Person(id: 1, name: "Ed Sheeran", age: 26, gender: .male),
Person(id: 2, name: "Phil Collins", age: 66, gender: .male),
Person(id: 3, name: "Shakira", age: 40, gender: .female),
Person(id: 4, name: "Rihanna", age: 25, gender: .female),
Person(id: 5, name: "Bono", age: 57, gender: .male)
]
对它进行排序依据的属性传递如何编写一个通用的扩展阵列,? (例如persons.sort(姓名)或cars.sort(制造商))
谢谢!
您可以在'sort()'方法中将属性名称作为字符串传递。然后在你的课堂上添加这个:https://stackoverflow.com/a/24919834/6638533 – samAlvin
@samAlvin他问的是Swift,而不是C#。 – Alexander
@亚历山大哎呦我的坏,我应该在将来更加小心 – samAlvin