我想上传多个图像,我一次插入数据到多个表。当用户填写表格时,首先将一些数据插入到table A
中,并将inserted_id
插入到table B
中。这是我的编码看起来像。使用codeigniter插入多个图像
控制器
$filesCount = count($_FILES['picture']['name']); //my input file name = 'picture'
for ($i = 0; $i < $filesCount; $i++) {
$_FILES['userFile']['name'] = $_FILES['picture']['name'][$i];
$_FILES['userFile']['type'] = $_FILES['picture']['type'][$i];
$_FILES['userFile']['tmp_name'] = $_FILES['picture']['tmp_name'][$i];
$_FILES['userFile']['error'] = $_FILES['picture']['error'][$i];
$_FILES['userFile']['size'] = $_FILES['picture']['size'][$i];
$config['upload_path'] = '/uploads/user/test/';
$config['allowed_types'] = 'gif|jpg|png';
$config['max_size'] = 0;
$new_name = uniqueId();
$config['file_name'] = $new_name;
$this->load->library('upload', $config);
if($this->upload->do_upload('userFile')){
$fileData = $this->upload->data();
$uploadData[$i]['file_name'] = $fileData['file_name'];
}
}
if(!empty($uploadData)) {
$this->Insert_model->setImage($uploadData);
$isCreate = $this->Insert_model->createImage($uploadData);
}
Insert_model
public function createImage($data = array()){
$this->db->trans_begin();
$userInfo = array(
'user_id' => $this->getUserId(), //UserId fetch from session
'title' => $this->getTitle(),
'description' => $this->getDescription(),
);
$this->db->insert('UserInfo', $userInfo); //Data inserted to table UserInfo first
$insert_id = $this->db->insert_id(); //And getting the inserted_id
$data[] = array(
'user_id' => $this->getUserId(),
'title_id' => $insert_id, //Insert Inserted id
'image_name' => $this->getImage(),
);
$this->db->insert_batch('UserImage', $data); //Insert data to table UserImage
if ($this->db->trans_status() === FALSE)
{
$this->db->trans_rollback();
}
else
{
$this->db->trans_commit();
return ($this->db->affected_rows() != 1) ? false : true;
}
}
数据的输出插入到表UserImage
Array
(
[0] => Array
(
[file_name] => 5943442cd1380.jpg
)
[1] => Array
(
[file_name] => 5943442cd1380.png
)
[2] => Array
(
[user_id] => 2
[title_id] => 1
[image_name] => Array
(
[0] => Array
(
[file_name] => 5943442cd1380.jpg
)
[1] => Array
(
[file_name] => 5943442cd1380.png
)
)
)
)
使用输出,无法将数据插入到第二个表中。
预期产出将
Array
(
[0] => Array
(
[user_id] => 2
[title_id] => 1
[file_name] => 5943442cd1380.jpg
)
[1] => Array
(
[user_id] => 2
[title_id] => 1
[file_name] => 5943442cd1380.png
)
)
这是因为在模型中,你的参数是'$ data'。而且你只在控制器中插入文件名并传递给模型。 –
我该如何从控制器获取'inserted_id'? –
你有没有尝试过在多个图像,如果任何图像不正确或不符合标准那么会发生什么? –