尝试更新一个表与另一个表

我有一个总帐表与人相处以下三列不列入简洁：尝试更新一个表与另一个表

**gl_account id** | **gl_amount** | **GL_adjustmentAmount** 
    9500   |  NULL  |  NULL 
    ...   | ...   |  ...

我有不同的调整表从不同的列上面除了两个：

**gl_account id** | **GL_adjustmentamount** 
    9500   |   289.84 
    9500   |   9.63 
    9500   |   13646.11 
    9500   |   835.31 
    9500   |   -210 
    9500   |   -1019.02 
    9500   |   -200

我需要更新总帐表包括所有7个新gl_adjustments但我t只包含289.84的值中的一个。

这是我的代码。

UPDATE LedgerTable 
SET [GL_adjustmentamount] = adjust.GL_adjustmentamount 
FROM LedgerTable AS genLed 
    FULL OUTER JOIN AdjustmentTable AS adjust 
    ON genLed.gl_accountid = adjust.gl_accountid

来源

2016-07-25 Ace

您的预期结果是什么？你是否想“总结”这些值？ – sgeddes

您是否希望在记帐表中的所有调整总数中有记录？如果是这样，你想聚集在一个cte /子查询然后更新，否则，如果你想每调整一个记录，你需要'INSERT'而不是''UPDATE'。 –

我正在使用sql 2008.我想最初在总帐中拥有每个GL_adjustedamount，但我认为总和值将是BEST。 :) – Ace

案例1：更新只为一个帐户

，如果你想这对于只有一个帐户，您可以使用此：

declare @AccountID INT 
set @AccountID = 9500 

update Ledger 
set  GL_adjustmentAmount = GL_adjustmentAmount + (select  SUM(a.GL_AdjustmentAmount) 
                from  Adjustment a 
                where  a.GL_AccountID = @AccountID) 
where GL_AccountID = @AccountID

你要知道，在accountId将不得不在这里指定。

案例2：如果您希望这对所有账户工作（应该&更可能是这种情况），那么你就需要一个更“广义”查询更新所有帐户的

那种东西：

update Ledger 
set  GL_AdjustmentAmount = ISNULL(GL_AdjustmentAmount,0) + ISNULL(collatedAdjustments.adjustment, 0) 
from Ledger ledger 
inner join 
(select   a.GL_AccountID, 
       SUM(a.GL_AdjustmentAmount) as Adjustment 
from   Adjustment adjustments 
group by  adjustments.GL_accountID) as collated 
on    ledger.GL_accountID = collated.GL_accountID

下面是一些你可以测试这个对一些样本数据：

CREATE TABLE Ledger(GL_AccountID int, GL_Amount int, GL_AdjustmentAmount int); 
CREATE TABLE Adjustment(GL_AccountID int, GL_AdjustmentAmount int); 

INSERT INTO Ledger(GL_AccountID,GL_Amount, GL_AdjustmentAmount) VALUES(9500, null, null); 
INSERT INTO Ledger(GL_AccountID,GL_Amount, GL_AdjustmentAmount) VALUES(9600, null, null); 
INSERT INTO Ledger(GL_AccountID,GL_Amount, GL_AdjustmentAmount) VALUES(9700, null, null); 
INSERT INTO Ledger(GL_AccountID,GL_Amount, GL_AdjustmentAmount) VALUES(9800, null, null); 

INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, 289.84); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, 9.63); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, 13646.11); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, 835.31); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, -210); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, -1019.02); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, -200); 

INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, 29.84); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, 29.63); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, 16646.11); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, 335.31); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, -1210); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, -2019.02); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, -1200); 

INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9700, 2239.02); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9700, 1400); 

INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9800, 4121.02); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9800, 1234);

该查询还将以前的任何调整（在ledger表中）也纳入公式中。

希望这有助于！

来源

2016-07-25 16:15:05

东西告诉我OP没有通过帐户ID。 – sgeddes

也许你想要包含'Ledger.GL_AdjustmentAmount'而不仅仅是替换它？即'设置GL_AdjustmentAmount = GL_AdjustmentAmount + ...' – Glenn

@Glenn这是一个很好的观点。相应地更新了答案。 –

select * into LedgerTable 
from Adjustment Table

来源

2016-07-25 20:17:05 abcool

尝试更新一个表与另一个表

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