1

我使用SQL 2005,与数以百万计的记录现有数据(所以数据结构不能改变),我试图做到以下几点:充分利用自参照表分层数据在SQL 2005

我在自引用表中有一些数据(下面的示例来自另一个问题,并进行了一些修改以显示我试图实现的内容)。我需要拔出结果的树格式如下:

Parent 
Child1 of Parent 
    Child1 of Child 1 
    Child2 of Child 1 
Child2 of Parent 
    Child1 of Child 2 

我的实际数据变为9级深 - 我试图让使用CTE的结果。然而,这将产生以下:

Parent 
Child1 of Parent 
Child2 of Parent 
    Child1 of Child 1 
    Child2 of Child 1 
    Child1 of Child 2 

这里是我使用的排序查询的一个例子:

create table workshop (
w_id smallint primary key, 
p_id smallint, 
s_date smalldatetime, 
title varchar(100)) 
go 

alter table workshop add constraint fk_wkshp foreign key (p_id) 
references workshop(w_id) 
go 

insert into workshop (w_id, p_id, s_date, title) values (1, null, 
'5/2/2007', 'Parent') 
insert into workshop (w_id, p_id, s_date, title) values (2, 1, 
'5/3/2007', 'Child 1 of the parent') 
insert into workshop (w_id, p_id, s_date, title) values (3, 1, 
'5/5/2007', 'Child 2 of the parent') 
insert into workshop (w_id, p_id, s_date, title) values (4, 2, 
'5/4/2007', 'Child of Child 1') 
insert into workshop (w_id, p_id, s_date, title) values (5, 2, 
'5/5/2007', 'Child 2 of the child of the parent') 
insert into workshop (w_id, p_id, s_date, title) values (6, 3, 
'5/7/2007', 'Child of the child 2') 
insert into workshop (w_id, p_id, s_date, title) values (7, null, 
'5/7/2007', '2nd Parent') 
insert into workshop (w_id, p_id, s_date, title) values (8, 7, 
'5/7/2007', 'Child of 2nd Parent') 
insert into workshop (w_id, p_id, s_date, title) values (9, 7, 
'5/7/2007', 'Child of 2nd Parent') 
go 

declare @id smallint 
set @id = 1 

;with events (w_id, p_id, s_date, title) 
as 
(
-- the anchor member 
select 
w_id, p_id, s_date, title 
from 
workshop 
where w_id = @id 

-- the recursive member 
union all 

select 
w.w_id, w.p_id, w.s_date, w.title 
from 
workshop w 
-- the key is to join to the CTE 
join events e on e.w_id = w.p_id 
) 

select * from events 

drop table workshop 
go 

我已经看到了关于这个其他各种问题,但不能看到的答案,我问题。 nearset的东西是oracle'通过事先连接',如果我使用的是oracle dB,那将会很棒!有任何想法吗?

干杯, 杰森

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我认为这是同一个问题http://stackoverflow.com/questions/539155/ordering-hierarchy-from-recursive-query-results-in-sql-2005是相同的问题。 – gjvdkamp 2011-03-31 10:03:47

+0

是的,你是对的 - 感谢这个评论我找到了我的答案(下面!) – Jay 2011-03-31 11:52:20

回答

0

我想我已经找到这是我要加入锚固构件上,而不是在车间桌子答案。感谢gjvdkamp这个类似的帖子,这让我重新评估了错误的'真实'sql语句。