2011-07-24 19 views
0

我与SDL瞎搞之前,我决定把打开的图像为背景,以主“屏幕”的程序,并使其动态的,所以不同大小的图像将导致不同大小的屏幕。问题是,我不明白为什么它不让我。我可以编译,但是当我尝试创建屏幕时,程序会报错,因为背景图像因某些未知原因而被清空。任何想法为什么?SDL使影像画面不工作

程序是非常小:

#include <iostream> 
#include "SDL/SDL.h" 
#define bpp 32 

int init(){ 
    if (SDL_Init(SDL_INIT_EVERYTHING) == -1) 
     return 1; 
    // will init ttf later 
    return 0; 
} 

SDL_Surface * open_image(std::string image_name){ 
    SDL_Surface * loaded_image = SDL_LoadBMP(image_name.c_str()); 
    if (loaded_image){ 
     SDL_Surface * optimized_image = SDL_DisplayFormat(loaded_image); // becomes NULL 
     SDL_FreeSurface(loaded_image); 
     return optimized_image; 
    } 
    return loaded_image; 
} 

int main(int argc, char * argv[]){ 
    if (init()) 
     return 1; 

    SDL_Surface * background = open_image("hello.bmp"); 
    SDL_Surface * screen = SDL_SetVideoMode(background -> w, background -> h, bpp, SDL_SWSURFACE); // erroring here 

    SDL_BlitSurface(background, NULL, screen, NULL); 
    if (SDL_Flip(screen) == -1) 
     return 1; 
    bool quit = false; 
    SDL_Event event; 
    while (!quit) 
     while (SDL_PollEvent(&event)) 
      if (event.type == SDL_QUIT) 
       quit = true; 
    return 0; 
} 

我收到提示3,这显然是访问不存在的值。在这种情况下,背景为w和h,因为背景为NULL,即使它不应该是

+0

是编译错误或运行时错误? –

+0

我编辑了我的问题。它的运行时错误 – calccrypto

+0

所以错误是在open_image?从哪里来? SDL_LoadBMP已经导致NULL还是SDL_DisplayFormat? – Bart

回答

2

您不能在调用SDL_DisplayFormat而不调用SDL_SetVideoMode之前一次。

我定你的代码:

SDL_Surface * screen = SDL_SetVideoMode(512, 512, bpp, SDL_SWSURFACE); 
    SDL_Surface * background = open_image("hello.bmp"); 
    screen = SDL_SetVideoMode(background -> w, background -> h, bpp, SDL_SWSURFACE); 
+0

真的吗?哇。我想我有一个关于sdl的投诉:( – calccrypto

+1

这是因为SDL_DisplayFormat取决于bpp和你只在SDL_SetVideoMode中给出的标志。 –