我在列表中有一个列表,我尝试遍历一个列表,然后在内部列表中查找一个值,如果存在该值,列表中的变量。在Python中对多个列表进行迭代
这里是我有,这似乎并没有做这项工作:
for z, g in range(len(tablerows), len(andrewlist)):
tablerowslist = tablerows[z]
if "Andrew Alexander" in tablerowslist:
andrewlist[g] = tablerowslist
任何想法?
这是列表结构:
[['Kyle Bazzy', 'FUP dropbox message', '8/18/2011', 'Swing Trade Stocks</a>', ' ', 'Affiliate blog'], ['Kyle Bazzy', 'FUP dropbox message', '8/18/2011', 'Swing Trade Software</a>', ' ', 'FUP from dropbox message. Affiliate blog'], ['Kyle Bazzy', 'FUP dropbox message', '8/18/2011', 'Start Day Trading (Blog)</a>', ' ', 'FUP from dropbox message'], ['Kyle Bazzy', 'Call, be VERY NICE', '8/18/2011', ' ', 'r24867</a>', 'We have been very nice to him, but he wants to cancel, we need to keep being nice and seeing what is wrong now.'], ['Jason Raznick', 'Reach out', '8/18/2011', 'Lexis Nexis</a>', ' ', '-'], ['Andrew Alexander', 'Check on account in one week', '8/18/2011', ' ', 'r46876</a>', '-'], ['Andrew Alexander', 'Cancel him from 5 dollar feed', '8/18/2011', ' ', 'r37693</a>', '-'], ['Aaron Wise', 'FUP with contract', '8/18/2011', 'YouTradeFX</a>', ' ', "Zisa is on vacation...FUP next week and then try again if she's still gone."], ['Aaron Wise', 'Email--JASON', '8/18/2011', 'Lexis Nexis</a>', ' ', 'email by today'], ['Sarah Knapp', '3rd FUP', '8/18/2011', 'Steven L. Pomeranz</a>', ' ', '-'], ['Sarah Knapp', 'Are we really interested in partnering?', '8/18/2011', 'Reverse Spins</a>', ' ', "V. political, doesn't seem like high quality content. Do we really want a partnership?"], ['Sarah Knapp', '2nd follow up', '8/18/2011', 'Business World</a>', ' ', '-'], ['Sarah Knapp', 'Determine whether we are actually interested in partnership', '8/18/2011', 'Fayrouz In Dallas</a>', ' ', "Hasn't updated since September 2010."], ['Sarah Knapp', 'See email exchange w/Autumn; what should happen', '8/18/2011', 'Graham and Doddsville</a>', ' ', "Wasn't sure if we could partner bc of regulations, but could do something meant simply to increase traffic both ways."], ['Sarah Knapp', '3rd follow up', '8/18/2011', 'Fund Action</a>', ' ', '-']]
对于在它有一个特定值的任何值,比方说,安德鲁·亚历山大,我要让这些单独的列表。
例如:
[['Andrew Alexander', 'Check on account in one week', '8/18/2011', ' ', 'r46876</a>', '-'], ['Andrew Alexander', 'Cancel him from 5 dollar feed', '8/18/2011', ' ', 'r37693</a>', '-']]
你必须明确你的数据结构是什么样子。你只有两个列表,还是你有一个列表,其中的每个元素是另一个列表?假设有多场比赛,你想收集所有的比赛吗? –
您可能正在寻找:'zip(范围(len(tablerows)),范围(len(andrewlist)))''。但仍然不明白代码试图做什么。你应该举一些例子输入和输出。 – utdemir