SELECT a.cp_node_id,
a.cmi_node_id,
a.user_id,
a.learner_name,
a.completion_status,
a.success_status,
b.id title,
c.dep,
d.field_id,
d.value
FROM cmi_node a
JOIN cmi_objective b
ON a.cmi_node_id=b.cmi_node_id
AND a.completion_status = 'completed'
AND a.success_status = 'passed'
AND a.cp_node_id = '1'
JOIN usr_data c
ON a.user_id = c.usr_id
JOIN udf_text d
ON a.user_id = d.usr_id
GROUP BY a.cmi_node_id
以我“d”表我有一列,有两个结果,例如:SQL(JOIN) - 两个结果从一列到两个列
ID: field_id: value:
1 1 test
1 2 text2
2 1 test
2 2 text3
3 1 test2
3 2 text6
etc...
在field_in始终是1或2.
我需要从 “cmi_node” 打印我的所有用户,例如:
user_id learner_name
1 George
2 Michel
3 James
我想从 “d” 表中添加两个列: 例如:
user_id learner_name field_in_first field_in_second value_first value_second
1 George 1 2 test text2
2 Michel 1 2 test text3
3 James 1 2 test2 text6
谢谢
MySQL或SQL服务器? – Jens
它的mysql ............ –