2009-05-22 64 views
0

我有一张表格,里面有一些遗留数据,我怀疑可能会有些混乱。这是一个多对多的连接表。如何计算MySQL中非唯一的值组合?

LIST_MEMBERSHIPS 
---------------- 
list_id 
address_id 

我想运行一个查询,将统计每个list_id的出现 - address_id对,并显示出发生从最高计数每到最低出现的次数。

我知道它需要涉及COUNT()GROUP BY,对吧?

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什么是你的表定义像你LIST_MEMBERSHIPS表? – 2009-05-22 00:08:46

回答

4
select list_id, address_id, count(*) as count 
from LIST_MEMBERSHIPS 
group by 1, 2 
order by 3 desc 

您可能会发现它有用添加

having count > 1 
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这似乎工作。谢谢! – Ethan 2009-05-22 00:14:41

1
select count(*), list_id, address_id 
from list_membership 
group by list_id, address_id 
order by count(*) desc