我发现了postgres的crosstab函数中一个奇怪的行为,我无法解释,但希望其他人可能...为什么空日期导致交叉表功能失败?
我使用的交叉表函数的版本需要先构建一个初步表。
此SQL成功地创建了初步表:
SELECT
ST.studyabrv||' '||S.labid||' '||S.subjectid||' '||S.box::varchar||' '||S.well AS "rowname",
M.marker AS "bucket",
G.allele1||' '||G.allele2 AS "bucket_value"
INTO TABLE ct
FROM
geno.gmarkers M,
geno.genotypes G,
geno.gsamples S,
geno.guploads U,
geno.gibg_studies ST
WHERE
G.markers_id=M.id
AND G.gsamples_id=S.id
AND S.guploads_id=U.id
AND U.ibg_study_id=ST.id
AND (M.id=5 OR M.id=6 OR M.id=2 OR M.id=4 OR M.id=3)
AND (S.labid='CL100001' OR S.labid='CL100002' OR S.labid='CL100003' OR S.labid='CL100004' OR S.labid='CL100005' OR S.labid='CL100006' OR S.labid='CL100007' OR S.labid='CL100008' OR S.labid='CL100009' OR S.labid='CL100010' OR S.labid='CL100011' OR S.labid='CL100012' OR S.labid='CL100013' OR S.labid='CL100014' OR S.labid='CL100015')
ORDER BY box,well;
,类似的产生输出:
rowname | bucket | bucket_value
--------------------------+-----------+--------------
LTS CL100001 10011 1 A01 | 5HTTLPR-T | S La
LTS CL100001 10011 1 A01 | 5HTTLPR-D | 14 16
LTS CL100001 10011 1 A01 | DAT1 | 440 480
LTS CL100001 10011 1 A01 | DRD4 | 475 475
LTS CL100001 10011 1 A01 | Caspi | 351 351
LTS CL100009 10420 1 A02 | Caspi |
LTS CL100009 10420 1 A02 | 5HTTLPR-T | La Lg
LTS CL100009 10420 1 A02 | 5HTTLPR-D | 16 16
LTS CL100009 10420 1 A02 | DAT1 | 440 480
LTS CL100009 10420 1 A02 | DRD4 | 475 475
...
但是,如果我尝试包括日期栏,里面全是空,如下所示:
SELECT
ST.studyabrv||' '||S.labid||' '||S.subjectid||' '||S.box::varchar||' '||S.well||' '||G.run_date::text AS "rowname",
M.marker AS "bucket",
G.allele1||' '||G.allele2 AS "bucket_value"
INTO TABLE ct
FROM
geno.gmarkers M,
geno.genotypes G,
geno.gsamples S,
geno.guploads U,
geno.gibg_studies ST
WHERE
G.markers_id=M.id
AND G.gsamples_id=S.id
AND S.guploads_id=U.id
AND U.ibg_study_id=ST.id
AND (M.id=5 OR M.id=6 OR M.id=2 OR M.id=4 OR M.id=3)
AND (S.labid='CL100001' OR S.labid='CL100002' OR S.labid='CL100003' OR S.labid='CL100004' OR S.labid='CL100005' OR S.labid='CL100006' OR S.labid='CL100007' OR S.labid='CL100008' OR S.labid='CL100009' OR S.labid='CL100010' OR S.labid='CL100011' OR S.labid='CL100012' OR S.labid='CL100013' OR S.labid='CL100014' OR S.labid='CL100015')
ORDER BY box,well;
这产生输出:
rowname | bucket | bucket_value
---------+-----------+--------------
| 5HTTLPR-T | S La
| 5HTTLPR-D | 14 16
| DAT1 | 440 480
| DRD4 | 475 475
| Caspi | 351 351
| Caspi |
| 5HTTLPR-T | La Lg
| 5HTTLPR-D | 16 16
正如你所看到的,将run_date列添加到“rowname”组合列的末尾会呈现整个组合空白......这是疯狂的。 如果我使用虚拟数据填充run_date,它将显示....但是如果它为空或空,这会导致“rowname”变为空白。
我不能说这是否是postgres中的错误,但如果可能的话,这是一个奇怪的结果,我想解决。
TIA, rixter
谢谢!将检查合并功能。 – rixter 2012-04-04 19:26:29
欢迎!只是不要为postgresql提出这样的错误:P – 2012-04-04 19:27:49
这个工作,使用用户同意的虚拟值:|| coalesce(G.run_date,'01/01/1900'):: text – rixter 2012-04-04 19:33:19