8
你能告诉我如何传递一个JSON字符串,它看起来像这样:如何解析JSON到目标C - SBJSON
{"lessons":[{"id":"38","fach":"D","stunde":"t1s1","user_id":"1965","timestamp":"0000-00-00 00:00:00"},{"id":"39","fach":"M","stunde":"t1s2","user_id":"1965","timestamp":"0000-00-00 00:00:00"}]}
我想它是这样的:
SBJSON *parser =[[SBJSON alloc] init];
NSArray *list = [[parser objectWithString:JsonData error:nil] copy];
[parser release];
for (NSDictionary *stunden in list)
{
NSString *content = [[stunden objectForKey:@"lessons"] objectForKey:@"stunde"];
}
感谢推进你的JSON数据结构如下
问候
谢谢:)不知道在哪里:) – Chris 2011-02-07 10:15:02