如何选择具有最小值的不同行

Question

我想要一条SQL语句来获取具有最小值的行。

数据库

ig_idx ig_team1 ig_team2 rl_league rl_image   rl_sports ig_status cnt 
410296 aaaaa  xxxxx  BRA D2  icon_BRA D2.png 7   S   3 
410298 aaaaa  xxxxx  BRA D2  icon_BRA D2.png 7   S   3 
410299 aaaaa  yyyyy  BRA D2  icon_BRA D2.png 7   S   3 
410301 bbbbb  yyyyy  BRA D2  icon_BRA D2.png 7   S   2 
410304 bbbbb  yyyyy  BRA D2  icon_BRA D2.png 7   S   2 
410306 ccccc  zzzzz  BRA D2  icon_BRA D2.png 7   S   2 

如何选择具有在点列中的最小值的ID？像这样...

ig_idx ig_team1 ig_team2 rl_league rl_image   rl_sports ig_status cnt 
410296 aaaaa  xxxxx  BRA D2  icon_BRA D2.png 7   S   3 
410301 bbbbb  yyyyy  BRA D2  icon_BRA D2.png 7   S   2 
410306 ccccc  zzzzz  BRA D2  icon_BRA D2.png 7   S   2 

Answer 1

使用row_number()：

select t.* 
from (select t.*, 
      row_number() over (partition by ig_team order by ig_idx asc) as seqnum 
     from t 
    ) t 
where seqnum = 1; 

Answer 2

看起来像它一样简单：

SELECT MIN(ig_idx), ig_team1, ig_team2, r1_league, r1_image, r1_sports, ig_status, cnt 
FROM t 
GROUP BY ig_team1, ig_team2, r1_league, r1_image, r1_sports, ig_status, cnt