0
;with Ranked(Empid,Mngrid,Empnm,RN,level) As
(select Empid,Mngrid ,Empnm ,row_number() over (order by Empid)AS RN ,
0 as level from dbo.EmpMngr),
AnchorRanked(Empid,Mngrid,Empnm,RN,level)
AS(select Empid,Mngrid,Empnm,RN ,level from Ranked),
RecurRanked(Empid,Mngrid,Empnm,RN,level)
AS(select Empid,Mngrid,Empnm,RN,level from AnchorRanked
Union All
select Ranked.Empid,Ranked.Mngrid,Ranked.Empnm,Ranked.RN,Ranked.level + 1
from Ranked
inner join RecurRanked
on Ranked.Empid = RecurRanked.Empid AND
Ranked.RN = RecurRanked.RN+1)
select Empid,Empnm,level from RecurRanked
您可以编辑您的问题,以便它是可读的,请 – kamahl 2010-06-08 20:35:09
日Thnx我想找到员工级别喜欢谁COMES IN X 1,Y 2,Z 2 A 3,B 3,C 4 – Vicky 2010-06-08 23:21:57
这是我如何想要输出 – Vicky 2010-06-08 23:22:20