加入查询问题 - 加入附近的语法错误

Question

TRADERS           INCENTIVE 
    __________________________________________  _____________ 
    TRDID NAME SUPERVISOR LOCATION PAY   TRDID INCENTIVE 
    ------------------------------------------  ------------- 
    66 Chad     NY   110000  17 5000 
    17 Yena   66  TN   75000  21 2000 
    5 Karam   66  TN   80000   66 5000 
    21 Rose   5  HI   100000  ... 


--group by highest pay for location and traderid            

        select e.trdid trdid, e.location, max (e.pay+ coalesce(b.incentive, 0)) maxtotal from traders e 
         join incentive b on e.trdid = b.trdid 
          group by e.location, trdid 
        join (      
        (select e.trdid trdid, max (e.pay+ coalesce(b.incentive, 0)) maxtotal from traders e 
       join incentive b on e.trdid = b.trdid 
       group by e.location, e.trdid)) using (trdid) 

我尝试连接表及其子查询时遇到错误。 我正在PostgreSQL上尝试这个

我想在每个位置只能得到最高收入的交易者，这是基于薪酬和奖励排名作为总额的排名。我想打印 交易员姓名，工资，奖励和总工资（工资加奖励）。

请你能指教我的查询有什么问题吗？我得到一个错误，指出语法错误附近加入

Answer 1

这是您的查询，排序的格式：

select e.trdid trdid, e.location, max (e.pay+ coalesce(b.incentive, 0)) maxtotal 
from traders e join incentive 
    b 
    on e.trdid = b.trdid 
group by e.location, trdid join 
    ((select e.trdid trdid, max (e.pay+ coalesce(b.incentive, 0)) as maxtotal 
     from traders e join 
      incentive b 
      on e.trdid = b.trdid 
     group by e.location, e.trdid 
    )) 
    using (trdid) 

你似乎误解SQL语法。 JOIN是仅在FROM条款中理解的运营商。 GROUP BY是一个单独的条款。它在条款FROM条款后。我想你打算：

select e.trdid trdid, e.location, max(e.pay + coalesce(b.incentive, 0)) maxtotal 
from traders e join 
    incentive b 
    on e.trdid = b.trdid join 
    (select e.trdid trdid, max(e.pay+ coalesce(b.incentive, 0)) as maxtotal 
     from traders e join 
      incentive b 
      on e.trdid = b.trdid 
     group by e.location, e.trdid 
    ) b 
    using (trdid) 
group by e.location, trdid; 

您可能会注意到我格式化我的查询，所以SQL子句在左边对齐。这就是为什么FROM和GROUP BY在左边，但是JOIN不是。

但是，我觉得写的查询更简单的方法是：

select distinct on (e.trdid) e.trdid as trdid, e.location, 
     max(e.pay + coalesce(b.incentive, 0)) as maxtotal 
from traders e join 
    incentive b 
    on e.trdid = b.trdid 
group by e.trdid, e.location 
order by e.trdid, maxtotal desc 

Answer 2

你不能真正做到：

select .... from .... 
join ... on .... 
group by .... 
join .... 

如果你想连接两个聚合子查询，使用公用表表达式（with条款）。更好的是尝试做你的设定操作，然后聚集在最后。