这是我第一次使用JQuery AJAX,所以我对语法不是很熟悉。现在我从数据库中提取一组值并填充下拉框。我需要AJAX做的是当他们从下拉框中选择时,用硬编码信息填充其他三个字段。一旦我得到AJAX正常工作,然后我想查询数据库并根据他们从下拉列表中选择返回结果。JQuery AJAX - 填充文本框和dropbown框
<div class="panel-body">
<div class="form-group">
<label for="nomName" class="col-sm-3 control-label">Name:</label>
<div class="col-sm-8">
<input type="text" class="form-control" data-validation="required" name="nomName" id="nomName" placeholder="Name" maxlength="50">
</div>
</div>
<div class="form-group">
<label for="nomTitle" class="col-sm-3 control-label">Title:</label>
<div class="col-sm-8">
<input type="text" class="form-control" data-validation="required" name="nomTitle" id="nomTitle" placeholder="Title" maxlength="50">
</div>
</div>
<div class="form-group">
<label for="nomDept" class="col-sm-3 control-label">Department:</label>
<div class="col-sm-8">
<select class="form-control" name="nomDept" id="nomDept">
<option value="" disabled selected>Select a Department...</option>
<option value="Building Services">Building Services</option>
<option value="Construction Management">Construction Management</option>
</select>
</div>
</div>
<div class="form-group">
<label for="nomGUID" class="col-sm-3 control-label">AU Email/GUID:</label>
<div class="col-sm-8">
<select class="form-control" name="nomGUID" id="nomGUID">
<option value="" disabled selected>Select a Person...</option>
<?php
while($row = mssql_fetch_array($user_list)){
echo "<option value=\"" . $row['id'] . "\">" . $row['id'] . "</option>";
}
?>
</select>
</div>
</div>
</div>
这里是我的AJAX。我知道这是不正确的,所以如果他们提供解决方案,我会很欣赏某人的解决方案。谢谢。
$(function() {
var options = {
"Option 1": "value 1",
"Option 2": "value 2",
"Option 3": "value 3"
}
$('#nomGUID').change(function() {
$.ajax({
url: 'test.php',
success: function('#options') {
$('#nomDept').empty();
$('#nomTitle').html('Test AJAX');
}
})
}
}
谢谢!尽管我不得不稍微编辑一下,但这最终为我工作。这里有一个小提琴,以防任何人感兴趣https://jsfiddle.net/collint25/bc8qdk3n/1/ – collint25