MySQL查询有两个条件内嵌SELECT的

有两个表，校友的表和缴款表 - 每一个贡献主要来自校友的ID
获取列表相关有的校友在2002-10-10和2003-10-10的日期范围内贡献2-3000。
结果需要显示校友的姓名，ID，每个校友的总所有时间给出，而且每个校友总给出了指定日期范围内

的尝试：

SELECT alumni.alumni_id, alumni.alumni_name, 
(SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id) AS contrib_alltime_total, 
(SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id AND contribution.date >= 2002-10-10 AND contribution.date <= 2003-10-10) AS contrib_range_total 

FROM alumni 
WHERE hold_code IS NULL  
ORDER BY lname ASC  
HAVING contrib_range_total >= 2000 
HAVING contrib_range_total <= 3000

我得到一个语法错误，很可能是因为我试图使用两个HAVING的

我也意识到你想使用一个HAVING与GROUP BY，但我不需要d o任何分组

我大概可以这样做，但我认为它效率低下，可能需要很长的时间

SELECT alumni.alumni_id, alumni.alumni_name, 
(SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id) AS contrib_alltime_total, 
(SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id AND contribution.date >= 2002-10-10 AND contribution.date <= 2003-10-10) AS contrib_range_total 

FROM alumni 

WHERE hold_code IS NULL 
AND (SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id AND contribution.date >= 2002-10-10 AND contribution.date <= 2003-10-10) >= 2000 
AND (SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id AND contribution.date >= 2002-10-10 AND contribution.date <= 2003-10-10) <= 3000 

ORDER BY lname ASC

什么将是实现这一目标的最快和最有效的方法是什么？任何意见是值得欢迎的，感谢您的时间

来源

2010-11-22 samJL

SELECT a.alumni_id, 
sum(c.contributed_amt) AS contrib_alltime_total, 
sum(case when c.contribution_date BETWEEN '2002-10-10' AND '2003-10-10' then c.contributed_amt else 0 end) AS contrib_range_total 
FROM alumni a 
INNER JOIN contribution c ON c.alumni_id = a.alumni_id 
WHERE a.hold_code IS NULL 
GROUP BY a.alumni_id 
HAVING contrib_range_total BETWEEN 2000 AND 3000

来源

2010-11-23 18:07:46 samJL

SELECT a.alumni_id, a.alumni_name, 
SUM(c.contributed_amt) AS contrib_alltime_total, 
SUM(c.contributed_amt) AS contrib_range_total 

FROM alumni a, contribution c 

WHERE a.hold_code IS NULL 
AND c.alumni_id = a.alumni_id AND c.date BETWEEN '2002-10-10' AND '2003-10-10' 
AND contrib_range_total BETWEEN 2000 AND 3000 
ORDER BY lname ASC

来源

2010-11-22 06:20:44

您的建议并不完美，所以我修改了它，但是我收到一条错误“组函数的使用无效” SELECT a.alumni_id，（SELECT SUM（contribute_amt）FROM contribution WHERE contribution.alu mni_id = a.alumni_id）AS contrib_alltime_total， SUM（c.contributed_amt）AS contrib_range_total FROM校友，贡献Ç WHERE a.hold_code IS NULL AND = c.alumni_id a.alumni_id AND BETWEEN c.contribution_date' 2002-10-10'AND'2003-10-10' AND SUM（c.contributed_amt）BETWEEN 2000 AND 3000 GROUP BY a.alumni_id ORDER BY a.lname ASC – samJL 2010-11-23 01:59:05

我不认为你可以使用HAVING没有GROUP BY，也使用AND加入多个HAVING箱子...

GROUP BY contrib_range_total HAVING contrib_range_total >= 2000 AND contrib_range_total <= 3000

来源

2010-11-22 06:24:04 superUntitled

MySQL查询有两个条件内嵌SELECT的

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