查询mysql有两个条件

Question

我想查询我的数据库，只显示收到至少60％的订购电话的记录。

这里是我的表中的一个精简版：

dealID | Ordered | Received | precreditEL | cancelled | precredit 
1  | 5  | 4  |    |   | 
2  | 2  | 2  |    |   | 
3  | 10  | 2  |    |   | 
4  | 8  | 8  | Non-applicable |   | 
5  | 6  | 5  | Non-applicable | Cancelled | Ready 

这里是我当前的查询

select deals.dealID,customer_info.accName,account_info.accessid,account_info.access_password,customer_info.contactNumber,deals.est_bill,deals.precreditAssigned,deals.precreditEL,deals.precredit 
from customer_info join deals 
left join account_info on account_info.custID = customer_info.custID 
left join phone_details on phone_details.dealID = deals.dealID 
where customer_info.custID = deals.custID 
and deals.precreditEL <> 'Non-applicable' 
and deals.precredit <> 'Complete' 
and deals.cancelled IS NULL 
GROUP BY deals.dealID 
having ((100 - (((sum(phone_details.ordered) - sum(phone_details.received))/sum(phone_details.ordered)) * 100)) >= 60) 

这完美的作品。只要precreditEL不是不适用，并且其未标记为已取消，该查询将给我已收到已订购订单的60％的记录。所以我的结果将是dealID 1 and 2。

但现在我需要添加另一个条件，绕过这种情况。如果precredit被标记为Ready，则无论上述条件如何，结果都将显示记录。所以我的结果将显示dealID 1, 2 and 5

任何帮助，将不胜感激。非常感谢你。

Answer 1

没关系，我把它通过改变

having ((100 - (((sum(phone_details.ordered) - sum(phone_details.received))/sum(phone_details.ordered)) * 100)) >= 60) 

到

having (((100 - (((sum(phone_details.ordered) - sum(phone_details.received))/sum(phone_details.ordered)) * 100)) >= 60) OR deals.precredit ='Ready')