如何使用带连字符的名称访问此对象属性？

Question

我正在使用某人写的与BaseCamp API接口的PHP类。

我正在做的特定调用是检索待办事项列表中的项目，该项目工作正常。

我的问题是，我不知道如何访问返回的对象的todo-items属性。下面是返回对象的后续代码var_dump：

object(stdClass)[6] 
    public 'completed-count' => string '0' (length=1) 
    public 'description' => string 'Description String' (length=89) 
    public 'id' => string '12345' (length=7) 
    public 'milestone-id' => string '' (length=0) 
    public 'name' => string 'Error Reports' (length=13) 
    public 'position' => string '1' (length=1) 
    public 'private' => string 'false' (length=5) 
    public 'project-id' => string '58904' (length=7) 
    public 'tracked' => string 'false' (length=5) 
    public 'uncompleted-count' => string '1' (length=1) 
    public 'todo-items' => 
    object(stdClass)[3] 
     public 'todo-item' => 
     object(stdClass)[5] 
      public 'completed' => string 'false' (length=5) 
      public 'content' => string 'content string here' (length=133) 
      public 'created-on' => string '2009-04-16T20:33:31Z' (length=20) 
      public 'creator-id' => string '23423' (length=7) 
      public 'id' => string '234' (length=8) 
      public 'position' => string '1' (length=1) 
      public 'responsible-party-id' => string '2844499' (length=7) 
      public 'responsible-party-type' => string 'Person' (length=6) 
      public 'todo-list-id' => string '234234' (length=7) 
    public 'complete' => string 'false' (length=5) 

我怎样才能访问该对象的todo-items部分？

Answer 1

<?php 
$x = new StdClass(); 
$x->{'todo-list'} = 'fred'; 
var_dump($x); 

所以，$ object - > {'todo-list'}是子对象。如果你可以这样设置，那么你也可以用同样的方法读取它。

如果你想将它转换为一个数组，它可以更容易一点（即显而易见的$ ret ['todo-list']访问），这段代码几乎是逐字从Zend_Config中获取的，并且会为你转换。

public function toArray() 
{ 
    $array = array(); 
    foreach ($this->_data as $key => $value) { 
     if ($value instanceof StdClass) { 
      $array[$key] = $value->toArray(); 
     } else { 
      $array[$key] = $value; 
     } 
    } 
    return $array; 
} 

Answer 2

试试这个最简单的方法！

$obj = $myobject->{'mydash-value'}; 
$objToArray = array($obj);