比较循环外部的字符串和循环外部的java

Question

我正在编写一个程序，从用户那里接受一个单词，如“香蕉”取出单词“b”的第一个字母，将它放在最后然后ananab检查它是否拼写相同的单词。我一直在做这个工作几天，并且尝试了几件事，但仍然不确定如何检查用户给出的字符串，其中有一个字符串在for循环中。这是我的计划到目前为止。

public static void main(String[] args) { 

    System.out.println("Enter words that can be checked for backward spelling"); 
    System.out.println("Please enter a word to check"); 
    Scanner keyboard = new Scanner(System.in); 

    String words = keyboard.nextLine(); 
    String firstLetter = String.valueOf(words.charAt(0)); 
    String words2 = words.substring(1); 
    String otherwords = words2+firstLetter; 


    for (int i=otherwords.length()-1; i>=0; i--){ 
     String newwords=String.valueOf(otherwords.charAt(i)); 
     boolean match = newwords.equalsIgnoreCase(words); 
     if (match){ 
      System.out.println("This word matches the criteria we are lookin for");} 
     } 
} 
} 

Answer 1

public static void main(String []args){ 

String input = new Scanner(System.in).nextLine(); 

char addToEnd = input.charAt(0); 
String newString = input.substring(1); 
newString+=addToEnd; 

if(input.equals(newString)){ 
System.out.println("This is a match"); 

} 

Answer 2

试试这个：

public static void main(String[] args) { 

    System.out.println("Enter words that can be checked for backward spelling"); 
    System.out.println("Please enter a word to check"); 
    Scanner sc = new Scanner(System.in); 
    String word = sc.nextLine(); 
    StringBuilder sb = new StringBuilder(); 
    sb.append(word.substring(1)); 
    sb.append(word.charAt(0)); 
    System.out.println(sb.toString().equals(word)?"This is a match.":"This is not a match."); 
} 

Answer 3

System.out.println("Enter words that can be checked for backward spelling"); 
System.out.println("Please enter a word to check"); 
Scanner keyboard = new Scanner(System.in); 
String word = keyboard.nextLine(); 
keyboard.close(); 
String firstLetter = word.substring(0, 1); 
String newWord = word.substring(1) + firstLetter; 
// reverse the word 
String reversedWord = ""; 
for (int i = 0; i < word.length(); i++) { 
    reversedWord = word.substring(i, i + 1) + reversedWord; 
} 
// check if it matches 
if (reversedWord.equalsIgnoreCase(newWord)) { 
    System.out.println("This word matches the criteria we are looking for!!!"); 
}