我试图在单个方法中通过Reactive接口IObservable返回HttpWebRequest POST方法的结果。我已经成功地使用下面的代码为GET方法做到这一点:是否有可能通过IObservable接口返回HttpWebRequest POST方法的结果
var request = (HttpWebRequest)WebRequestCreator.ClientHttp.Create(url);
request.Method = method;
request.Accept = GetHttpType();
request.CookieContainer = new CookieContainer();
return Observable.FromAsyncPattern(request.BeginGetResponse, ar => ProcessResponse(method, ar, request))()
.Select(r => r);
但我不确定如何链连同所需要的响应流的读取写入请求流的异步观察者用于HTTP POST操作。如何将以下变量obs1
& obs2
连接在一起,以便我可以返回obs2?
var request = (HttpWebRequest)WebRequestCreator.ClientHttp.Create(url);
var type = GetHttpType();
request.Method = method;
request.Accept = type;
request.ContentType = type;
request.CookieContainer = new CookieContainer();
var data = Serialize(requestResource);
var obs1 = Observable.FromAsyncPattern(request.BeginGetRequestStream, ar1 => ProcessRequest(method, data, ar1, request))
var obs2 = Observable.FromAsyncPattern(request.BeginGetResponse, ar2 => ProcessResponse(method, ar2, request))();
// How do I connect obs1 And obs2 together...
return obs2;
我还以为下面应该工作,但“ProcessResponse”方法不会被调用,没有人知道为什么吗?
var obs1 = Observable.FromAsyncPattern(request.BeginGetRequestStream, ar1 => ProcessRequest(method, data, ar1, request))();
var obs2 = Observable.FromAsyncPattern(request.BeginGetResponse, ar2 => ProcessResponse(method, ar2, request));
return obs1.SelectMany(a => obs2(), (a, b) => b);
他们不是相同类型,所以我不能连接,谢谢 – AwkwardCoder 2010-12-01 13:33:57
对不起,我当时没有太多关注。我会尽量不从'屁股'从现在开始:) – rawpower 2010-12-01 21:04:37