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如果通过我的HTML表格中的所有单元格我环路和各rowOBj添加在tableOBJ一个新的属性,它看起来像下面这样BUT ....遍历表以JSON
var tableOBJ = {};
$("table tr").each(function (index, value) {
var r = new rowOBJ(
$(this).find('td').eq(0).text(),
$(this).find('td').eq(1).text()
);
tableOBJ[index] = r;
});
var p = JSON.stringify(tableOBJ);
p =
{
"0":{"name":"fdgd","surname":"ssdt"},
"1":{"name":"fdsf","surname":"vn"},
"2":{"name":"dfsb","surname":"mry"},
"3":{"name":"hsdsdfry","surname":"smh"}
}
怎么办我做以前的样子使json看起来像这样
{
{"name":"fdgd","surname":"ssdt"},
{"name":"fdsf","surname":"vn"},
{"name":"dfsb","surname":"mry"},
{"name":"hsdsdfry","surname":"smh"}
}
你不会的,因为你要的是不是有效的JSON。 – cdhowie 2012-08-01 19:19:23